Given two arrays A and B of equal size. The task is to print any permutation of array A such that the number of indices i for which A[i] > B[i] is maximized.
Input: A = [12, 24, 8, 32], B = [13, 25, 32, 11] Output: 24 32 8 12 Input: A = [2, 7, 11, 15], B = [1, 10, 4, 11] Output: 2 11 7 15
If the smallest element in A beats the smallest element in B, we should pair them. Otherwise, it is useless for our score, as it can’t beat any other element of B.
With above strategy we make two vector of pairs, Ap for A and Bp for B with their element and respective index. Then sort both vectors and simulate them. Whenever we found any element in vector Ap such that Ap[i].first > Bp[j].first for some (i, j) we pair them i:e we update our answer array to ans[Bp[j].second] = Ap[i].first. However if Ap[i].first < Bp[j].first for some (i, j) then we store them in vector remain and finally pair them with any one.
Below is the implementation of above approach:
24 32 8 12
Time Complexity: O(N*log(N)), where N is the length of array.
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Improved By : rituraj_jain