Python provides direct methods to find permutations and combinations of a sequence. These methods are present in itertools package.
Permutation
First import itertools package to implement the permutations method in python. This method takes a list as an input and returns an object list of tuples that contain all permutations in a list form.
Python3
from itertools import permutations
perm = permutations([ 1 , 2 , 3 ])
for i in list (perm):
print (i)
|
Output:
(1, 2, 3)
(1, 3, 2)
(2, 1, 3)
(2, 3, 1)
(3, 1, 2)
(3, 2, 1)
Time complexity: O(n!), where n is the length of the input list. This is because there are n! permutations of n elements, and the program generates and prints all of them.
Auxiliary space: O(n!), as the program needs to store all n! permutations in memory before printing them out. Specifically, the perm variable created by calling permutations([1, 2, 3]) stores all n! permutations in memory as a list.
It generates n! permutations if the length of the input sequence is n.
If want to get permutations of length L then implement it in this way.
Python3
from itertools import permutations
perm = permutations([ 1 , 2 , 3 ], 2 )
for i in list (perm):
print (i)
|
Output:
(1, 2)
(1, 3)
(2, 1)
(2, 3)
(3, 1)
(3, 2)
The time complexity of this program is O(n^r) where n is the length of the input array and r is the length of permutations to be generated.
The space complexity is also O(n^r) as all permutations are stored in memory before printing.
It generates nCr * r! permutations if the length of the input sequence is n and the input parameter is r.
Combination
This method takes a list and an input r as an input and return an object list of tuples which contain all possible combination of length r in a list form.
Python3
from itertools import combinations
comb = combinations([ 1 , 2 , 3 ], 2 )
for i in list (comb):
print (i)
|
Output:
(1, 2)
(1, 3)
(2, 3)
1. Combinations are emitted in lexicographic sort order of input. So, if the input list is sorted, the combination tuples will be produced in sorted order.
Python3
from itertools import combinations
comb = combinations([ 1 , 2 , 3 ], 2 )
for i in list (comb):
print (i)
|
Output:
(1, 2)
(1, 3)
(2, 3)
2. Elements are treated as unique based on their position, not on their value. So if the input elements are unique, there will be no repeat values in each combination.
Python3
from itertools import combinations
comb = combinations([ 2 , 1 , 3 ], 2 )
for i in list (comb):
print (i)
|
Output:
(2, 1)
(2, 3)
(1, 3)
3. If we want to make a combination of the same element to the same element then we use combinations_with_replacement.
Python3
from itertools import combinations_with_replacement
comb = combinations_with_replacement([ 1 , 2 , 3 ], 2 )
for i in list (comb):
print (i)
|
Output:
(1, 1)
(1, 2)
(1, 3)
(2, 2)
(2, 3)
(3, 3)
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Last Updated :
08 Mar, 2023
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