When we pass a primitive type to a method, it is passed by value. But when we pass an object to a method, the situation changes dramatically, because objects are passed by what is effectively call-by-reference. Java does this interesting thing that’s sort of a hybrid between pass-by-value and pass-by-reference. Basically, a parameter cannot be changed by the function, but the function can ask the parameter to change itself via calling some method within it.
- While creating a variable of a class type, we only create a reference to an object. Thus, when we pass this reference to a method, the parameter that receives it will refer to the same object as that referred to by the argument.
- This effectively means that objects act as if they are passed to methods by use of call-by-reference.
- Changes to the object inside the method do reflect in the object used as an argument.
In Java we can pass objects to methods. For example, consider the following program :
ob1 == ob2: true ob1 == ob3: false
Illustrative images for the above program
- Three objects ‘ob1’ , ‘ob2’ and ‘ob3’ are created:
ObjectPassDemo ob1 = new ObjectPassDemo(100, 22); ObjectPassDemo ob2 = new ObjectPassDemo(100, 22); ObjectPassDemo ob3 = new ObjectPassDemo(-1, -1);
From the method side, a reference of type Foo with a name a is declared and it’s initially assigned to null.
boolean equalTo(ObjectPassDemo o);
- As we call the method equalTo, the reference ‘o’ will be assigned to the object which is passed as an argument, i.e. ‘o’ will refer to ‘ob2’ as following statement execute.
System.out.println("ob1 == ob2: " + ob1.equalTo(ob2));
Now as we can see, equalTo method is called on ‘ob1’ , and ‘o’ is referring to ‘ob2’. Since values of ‘a’ and ‘b’ are same for both the references, so if(condition) is true, so boolean true will be return.
if(o.a == a && o.b == b)
- Again ‘o’ will reassign to ‘ob3’ as the following statement execute.
System.out.println("ob1 == ob3: " + ob1.equalTo(ob3));
- Now as we can see, equalTo method is called on ‘ob1’ , and ‘o’ is referring to ‘ob3’. Since values of ‘a’ and ‘b’ are not same for both the references, so if(condition) is false, so else block will execute and false will be return.
Defining a constructor that takes an object of its class as a parameter
One of the most common uses of object parameters involves constructors. Frequently, in practice, there is need to construct a new object so that it is initially the same as some existing object. To do this, either we can use Object.clone() method or define a constructor that takes an object of its class as a parameter. The second option is illustrated in below example:
Volume of mybox is 3000.0 Volume of myclone is 3000.0
In java, a method can return any type of data, including objects. For example, in the following program, the incrByTen( ) method returns an object in which the value of a (an integer variable) is ten greater than it is in the invoking object.
ob1.a: 2 ob2.a: 12
Note : When an object reference is passed to a method, the reference itself is passed by use of call-by-value. However, since the value being passed refers to an object, the copy of that value will still refer to the same object that its corresponding argument does. That’s why we said that java is strictly pass-by-value.
This article is contributed by Gaurav Miglani. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to firstname.lastname@example.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.
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