Given a n-ary tree and a number x, find and return the number of nodes which are greater than x.
In the given tree, x = 7 Number of nodes greater than x are 4.
The idea is maintain a count variable initialize to 0. Traverse the tree and compare root data with x. If root data is greater than x, increment the count variable and recursively call for all its children.
Below is the implementation of idea.
Number of nodes greater than 5 are 2
This article is contributed by Chhavi. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to email@example.com. See your article appearing on the GeeksforGeeks main page and help other Geeks.
Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.
- Count the nodes of the tree which make a pangram when concatenated with the sub-tree nodes
- Number of unique paths in tree such that every path has a value greater than K
- Given a n-ary tree, count number of nodes which have more number of children than parents
- Number of special nodes in an n-ary tree
- Level with maximum number of nodes using DFS in a N-ary tree
- Count the number of nodes at given level in a tree using BFS.
- Number of leaf nodes in the subtree of every node of an n-ary tree
- Relationship between number of nodes and height of binary tree
- Number of ways to paint a tree of N nodes with K distinct colors with given conditions
- Print levels with odd number of nodes and even number of nodes
- Count all Grandparent-Parent-Child Triplets in a binary tree whose sum is greater than X
- Subtree of all nodes in a tree using DFS
- Sum of all nodes in a binary tree
- XOR of all the nodes in the sub-tree of the given node
- Sum of all leaf nodes of binary tree