# Minimum sum of absolute difference of pairs of two arrays

Given two arrays a[] and b[] of equal length n. The task is to pair each element of array a to an element in array b, such that sum S of absolute differences of all the pairs is minimum.

Suppose, two elements a[i] and a[j] (i != j) of a are paired with elements b[p] and b[q] of b respectively,
then p should not be equal to q.

Examples:

```Input :  a[] = {3, 2, 1}
b[] = {2, 1, 3}
Output : 0

Input :  n = 4
a[] = {4, 1, 8, 7}
b[] = {2, 3, 6, 5}
Output : 6
```

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

The solution to the problem is a simple greedy approach. It consists of two steps.
Step 1 : Sort both the arrays in O (n log n) time.
Step 2 : Find absolute difference of each pair of corresponding elements (elements at same index) of both arrays and add the result to the sum S. The time complexity of this step is O(n).

Hence, the overall time complexity of the program is O(n log n).

## C++

 `// C++ program to find minimum sum of absolute ` `// differences of two arrays. ` `#include ` `using` `namespace` `std; ` ` `  `// Returns minimum possible pairwise absolute ` `// difference of two arrays. ` `long` `long` `int` `findMinSum(``int` `a[], ``int` `b[], ``int` `n) ` `{ ` `    ``// Sort both arrays ` `    ``sort(a, a+n); ` `    ``sort(b, b+n); ` ` `  `    ``// Find sum of absolute differences ` `    ``long` `long` `int` `sum= 0 ; ` `    ``for` `(``int` `i=0; i

## Java

 `// Java program to find minimum sum of ` `// absolute differences of two arrays. ` `import` `java.util.Arrays; ` ` `  `class` `MinSum ` `{ ` `    ``// Returns minimum possible pairwise  ` `    ``// absolute difference of two arrays. ` `    ``static` `long` `findMinSum(``long` `a[], ``long` `b[], ``long` `n) ` `    ``{ ` `        ``// Sort both arrays ` `        ``Arrays.sort(a); ` `        ``Arrays.sort(b); ` `      `  `        ``// Find sum of absolute differences ` `        ``long` `sum = ``0` `; ` `        ``for` `(``int` `i = ``0``; i < n; i++) ` `            ``sum = sum + Math.abs(a[i] - b[i]); ` `      `  `        ``return` `sum; ` `    ``} ` `      `  `    ``// Driver code ` `    ``public` `static` `void` `main(String[] args)  ` `    ``{ ` `        ``// Both a[] and b[] must be of same size. ` `        ``long` `a[] = {``4``, ``1``, ``8``, ``7``}; ` `        ``long` `b[] = {``2``, ``3``, ``6``, ``5``}; ` `        ``int` `n = a.length; ` `        ``System.out.println(findMinSum(a, b, n)); ` `    ``}     ` `} ` `  `  `// This code is contributed by Raghav Sharma `

## Python3

 `# Python3 program to find minimum sum  ` `# of absolute differences of two arrays. ` `def` `findMinSum(a, b, n): ` ` `  `    ``# Sort both arrays ` `    ``a.sort() ` `    ``b.sort() ` ` `  `    ``# Find sum of absolute differences ` `    ``sum` `=` `0` `     `  `    ``for` `i ``in` `range``(n): ` `        ``sum` `=` `sum` `+` `abs``(a[i] ``-` `b[i]) ` ` `  `    ``return` `sum` ` `  `# Driver program ` `     `  `# Both a[] and b[] must be of same size. ` `a ``=` `[``4``, ``1``, ``8``, ``7``] ` `b ``=` `[``2``, ``3``, ``6``, ``5``] ` `n ``=` `len``(a) ` ` `  `print``(findMinSum(a, b, n)) ` ` `  `# This code is contributed by Anant Agarwal. `

## C#

 `// C# program to find minimum sum of ` `// absolute differences of two arrays. ` `using` `System; ` ` `  `class` `MinSum { ` `     `  `    ``// Returns minimum possible pairwise  ` `    ``// absolute difference of two arrays. ` `    ``static` `long` `findMinSum(``long` `[]a, ``long` `[]b, ` `                           ``long` `n) ` `    ``{ ` `         `  `        ``// Sort both arrays ` `        ``Array.Sort(a); ` `        ``Array.Sort(b); ` `     `  `        ``// Find sum of absolute differences ` `        ``long` `sum = 0 ; ` `        ``for` `(``int` `i = 0; i < n; i++) ` `            ``sum = sum + Math.Abs(a[i] - b[i]); ` `     `  `        ``return` `sum; ` `    ``} ` `     `  `    ``// Driver code ` `    ``public` `static` `void` `Main(String[] args)  ` `    ``{ ` `        ``// Both a[] and b[] must be of same size. ` `        ``long` `[]a = {4, 1, 8, 7}; ` `        ``long` `[]b = {2, 3, 6, 5}; ` `        ``int` `n = a.Length; ` `        ``Console.Write(findMinSum(a, b, n)); ` `    ``}  ` `} ` ` `  `// This code is contributed by parashar... `

## PHP

 ` `

Output :

```6
```

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Improved By : parashar, nitin mittal

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