Given an array of integers, find two non-overlapping contiguous sub-arrays such that the absolute difference between the sum of two sub-arrays is maximum.
Input: [-2, -3, 4, -1, -2, 1, 5, -3] Output: 12 Two subarrays are [-2, -3] and [4, -1, -2, 1, 5] Input: [2, -1, -2, 1, -4, 2, 8] Output: 16 Two subarrays are [-1, -2, 1, -4] and [2, 8]
Expected time complexity is O(n).
The idea is for each index i in given array arr[0…n-1], compute maximum and minimum sum subarrays that lie in subarrays arr[0…i] and arr[i+1 …n-1]. We maintain four arrays that store the maximum and minimum sums in the subarrays arr[0…i] and arr[i+1 … n-1] for every index i in the array.
leftMax : An element leftMax[i] of this array stores the maximum value in subarray arr[0..i] leftMin : An element leftMin[i] of this array stores the minimum value in subarray arr[0..i] rightMax : An element rightMax[i] of this array stores the maximum value in subarray arr[i+1..n-1] rightMin : An element rightMin[i] of this array stores the minimum value in subarray arr[i+1..n-1]
We can build above four arrays in O(n) time by using Kadane Algorithm.
- Kadane’s algorithm can be modified to find minimum absolute sum of a subarray as well. The idea is to change the sign of each element in the array and run Kadane Algorithm to find maximum sum subarray that lies in arr[0…i] and arr[i+1 … n-1]. Now invert the sign of maximum subarray sum found. That will be our minimum subarray sum. This idea is taken from here.
- abs(max sum subarray that lies in arr[0…i] – min sum subarray that lies in arr[i+1…n-1])
- abs(min sum subarray that lies in arr[0…i] – max sum subarray that lies in arr[i+1…n-1])
- Maximum product of sum of two contiguous subarrays of an array
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- Maximum absolute difference in an array
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- Maximum absolute difference of value and index sums
- Count maximum elements of an array whose absolute difference does not exceed K
- Find maximum number of elements such that their absolute difference is less than or equal to 1
- Partition into two subarrays of lengths k and (N - k) such that the difference of sums is maximum
- Partitioning into two contiguous element subarrays with equal sums
- Number of subarrays having absolute sum greater than K | Set-2
- Sliding Window Maximum (Maximum of all subarrays of size k) using stack in O(n) time
- Sliding Window Maximum (Maximum of all subarrays of size k)
- Triplets in array with absolute difference less than k
- Sort an array according to absolute difference with given value
- Maximum no. of contiguous Prime Numbers in an array
In order to calculate maximum sum subarray that lies in arr[0…i], we run Kadane Algorithm from 0 to n-1 and to find maximum sum subarray that lies in arr[i+1 … n-1], we run Kadane Algorithm from n-1 to 0.
Now from above four arrays, we can easily find maximum absolute difference between the sum of two contiguous sub-arrays. For each index i, take maximum of
Below is the implementation of above idea.
Time Complexity is O(n) where n is the number of elements in input array. Auxiliary Space required is O(n).
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Improved By : chitranayal