Skip to content
Related Articles

Related Articles

Minimum product of k integers in an array of positive Integers
  • Difficulty Level : Easy
  • Last Updated : 17 Feb, 2021
GeeksforGeeks - Summer Carnival Banner

Given an array of n positive integers. We are required to write a program to print the minimum product of k integers of the given array.
Examples: 
 

Input : 198 76 544 123 154 675
         k = 2
Output : 9348
We get minimum product after multiplying
76 and 123.

Input : 11 8 5 7 5 100
        k = 4
Output : 1400

 

The idea is simple, we find the smallest k elements and print multiplication of them. In below implementation, we have used simple Heap based approach where we insert array elements into a min heap and then find product of top k elements.
 

C++




// CPP program to find minimum product of
// k elements in an array
#include <bits/stdc++.h>
using namespace std;
 
int minProduct(int arr[], int n, int k)
{
    priority_queue<int, vector<int>, greater<int> > pq;
    for (int i = 0; i < n; i++)
        pq.push(arr[i]);
 
    int count = 0, ans = 1;
 
    // One by one extract items from max heap
    while (pq.empty() == false && count < k) {
        ans = ans * pq.top();
        pq.pop();
        count++;
    }
 
    return ans;
}
 
// Driver code
int main()
{
    int arr[] = {198, 76, 544, 123, 154, 675};
    int k = 2;
    int n = sizeof(arr) / sizeof(arr[0]);
    cout << "Minimum product is "
         << minProduct(arr, n, k);
    return 0;
}

Java




// Java program to find minimum product of
// k elements in an array
import java.util.PriorityQueue;
 
class GFG
{
    public static int minProduct(int[] arr, int n, int k)
    {
        PriorityQueue<Integer> pq = new PriorityQueue<>();
        for (int i = 0; i < n; i++)
            pq.add(arr[i]);
         
            int count = 0, ans = 1;
 
            // One by one extract items
            while(pq.isEmpty() == false && count < k)
            {
                ans = ans * pq.element();
                pq.remove();
                count++;
            }
         
            return ans;
    }
 
    // Driver Code
    public static void main(String[] args)
    {
        int arr[] = {198, 76, 544, 123, 154, 675};
        int k = 2;
        int n = arr.length;
        System.out.print("Minimum product is " +
                          minProduct(arr, n, k));
    }
}
 
// This code is contributed by sanjeev2552

Python3




# Python3 program to find minimum
# product of k elements in an array
import math
import heapq
 
def minProduct(arr, n, k):
 
    heapq.heapify(arr)
    count = 0
    ans = 1
 
    # One by one extract
    # items from min heap
    while ( arr ) and count < k:
        x = heapq.heappop(arr)
        ans = ans * x
        count = count + 1
     
    return ans;
 
# Driver method
arr = [198, 76, 544, 123, 154, 675]
k = 2
n = len(arr)
print ("Minimum product is",
       minProduct(arr, n, k))

C#




// C# program to find minimum product of
// k elements in an array
using System;
using System.Collections.Generic;
public class GFG
{
  public static int minProduct(int[] arr, int n, int k)
  {
    List<int> pq = new List<int>();
    for (int i = 0; i < n; i++)
      pq.Add(arr[i]);
 
    int count = 0, ans = 1;
 
    // One by one extract items
    while(pq.Count!=0 && count < k)
    {
      pq.Sort();
      ans = ans * pq[0];
      pq.RemoveAt(0);
      count++;
    }
 
    return ans;
  }
 
  // Driver Code
  public static void Main(String[] args)
  {
    int []arr = {198, 76, 544, 123, 154, 675};
    int k = 2;
    int n = arr.Length;
    Console.Write("Minimum product is " +
                  minProduct(arr, n, k));
  }
}
 
// This code is contributed by Rajput-Ji

Output: 
 

Minimum product is 9348

Time Complexity : O(n * log n) 
Note that the above problem can be solved in O(n) time using methods discussed here and here.
This article is contributed by Gitanjali Sharma. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.
Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.
 

Attention reader! Don’t stop learning now. Get hold of all the important DSA concepts with the DSA Self Paced Course at a student-friendly price and become industry ready.




My Personal Notes arrow_drop_up
Recommended Articles
Page :