Given a binary tree and a node in the binary tree, find Levelorder successor of the given node. That is, the node that appears after the given node in the level order traversal of the tree.
Note: The task is not just to print the data of the node, you have to return the complete node from the tree.
Consider the following binary tree 20 / \ 10 26 / \ / \ 4 18 24 27 / \ 14 19 / \ 13 15 Levelorder traversal of given tree is: 20, 10, 26, 4, 18, 24, 27, 14, 19, 13, 15 Input : 24 Output : 27 Input : 4 Output : 18
- Check if the root is NULL, that is tree is empty. If true then return NULL.
- Check if the given node is root. If true:
- Check if left child of root exists, if true return left child of root.
- Else, check if right child exists, return it.
- If the root is the only node. Return NULL.
- Otherwise, perform Level Order Traversal on the tree using a Queue.
- At every step of the level order traversal, check if the current node matches with the given node.
- If True, stop traversing any further and return the element at top of queue which will be the next node in the level order traversal.
Below is the implementation of the above approach:
LevelOrder successor of 24 is 27
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- Print extreme nodes of each level of Binary Tree in alternate order
- Print odd positioned nodes of odd levels in level order of the given binary tree
- Construct a complete binary tree from given array in level order fashion
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- Print even positioned nodes of even levels in level order of the given binary tree
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