Left rotation of an array using vectors in C++

Given an array arr[] of integers and another integer D, the task is to perform D left rotations on the array and print the modified array.

Examples:

Input: arr[] = {1, 2, 3, 4, 5, 6}, D = 2
Output: 3 4 5 6 1 2

Input: arr[] = {1, 2, 3, 4, 5, 6}, D = 12
Output: 1 2 3 4 5 6

Approach: Using vectors in C++, a rotation can be performed by removing the first element from the vector and then inserting it in the end of the same vector. Similarly, all the requried rotations can be performed and then print the contents of the modified vector to get the required rotated array.



Below is the implementation of the above approach:

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// C++ implementation of the approach
#include <bits/stdc++.h>
using namespace std;
  
// Function to left rotate the array by d elements
void rotate(vector<int> vec, int d)
{
  
    // Push first d elements from the beginning
    // to the end and remove those elements
    // from the beginning
    for (int i = 0; i < d; i++) {
        vec.push_back(vec[0]);
        vec.erase(vec.begin());
    }
  
    // Print the rotated array
    for (int i = 0; i < vec.size(); i++) {
        cout << vec[i] << " ";
    }
}
  
// Driver code
int main()
{
    vector<int> vec = { 1, 2, 3, 4, 5, 6 };
    int n = vec.size();
    int d = 2;
  
    rotate(vec, d % n);
  
    return 0;
}

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Output:

3 4 5 6 1 2


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