jQuery UI Button widget() Method
jQuery UI button widget() method returns an object which contains the visual representation of the button
Syntax:
$( ".selector" ).button("widget")
Parameters: This method does not accept any parameters.
Return values: This method returns an object value.
- Links for jQuery UI libraries:
<link rel=’stylesheet’
href=”http://ajax.googleapis.com/ajax/libs/jqueryui/1.8.16/themes/ui-lightness/jquery-ui.css”>
<script src=”https://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.js”> </script>
<script src=”https://ajax.googleapis.com/ajax/libs/jqueryui/1.8.16/jquery-ui.js”> </script>
- OR
<link rel=’stylesheet’
href=”https://code.jquery.com/ui/1.10.4/themes/ui-lightness/jquery-ui.css”>
<script src=”https://code.jquery.com/jquery-1.10.2.js”> </script>
<script src=”https://code.jquery.com/ui/1.10.4/jquery-ui.js”> </script>
Below are the example which shows the implementation of this method.
Example 1:
HTML
<!DOCTYPE html> < html > < head > < meta charset = "utf-8" > < meta name = "viewport" content = "width=device-width, initial-scale=1" > < script src = </ script > < script src = </ script > < link href = rel = "stylesheet" type = "text/css" /> < style > .height { height: 10px; } </ style > < script > $(function () { $("#buttonId, #submitId").button(); $('#buttonId, #submitId').click(function (event) { event.preventDefault(); var a = $( this ).button( "widget" ); console.log(a) }); }); </ script > </ head > < body > < h1 style = "color:green" >GeeksforGeeks</ h1 > < b >jQueryUI | Button widget Method</ b > < div class = "height" > </ div >< br > < div class = "buttons-div" > < button id = "buttonId" >Button element</ button > < input id = "submitId" type = "submit" value = "Submit button" > </ div > </ body > </ html > |
Output:
Reference: https://api.jqueryui.com/button/
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