jQuery UI Checkboxradio destroy() Method
Checkboxradio Widget destroy() method is used remove all functionality of checkboxradio button. It returns the element back to its pre-init state. This method does not accept any parameters.
Syntax:
$( ".selector" ).checkboxradio( "destroy" );
Approach: First, add jQuery UI scripts needed for your project.
<link href = “https://code.jquery.com/ui/1.10.4/themes/ui-lightness/jquery-ui.css” rel = “stylesheet”>
<script src = “https://code.jquery.com/jquery-1.10.2.js”></script>
<script src = “https://code.jquery.com/ui/1.10.4/jquery-ui.js”></script>
Example:
HTML
<!DOCTYPE html> < html > < head > < link href = rel = 'stylesheet' > < script src = </ script > < script src = </ script > </ head > < body > < center > < h1 style = "color:green" >GeeksforGeeks</ h1 > < h3 >Radio Button Example</ h3 > < label for = "radio1" >Button 1</ label > < input type = "radio" name = "radio" id = "radio1" class = 'radio' > < br > < label for = "radio2" >Button 2</ label > < input type = "radio" name = "radio" id = "radio2" class = 'radio' > < br > < label for = "radio3" >Button 3</ label > < input type = "radio" name = "radio" id = "radio3" class = 'radio' > < br >< br >< br > < h3 >Checkbox Example</ h3 > < label for = "checkbox1" >Checkbox 1</ label > < input type = "checkbox" name = "checkbox1" id = "checkbox1" class = 'checkbox' > < br > < label for = "checkbox2" >checkbox 2</ label > < input type = "checkbox" name = "checkbox2" id = "checkbox2" class = 'checkbox' > < script > $(document).ready(function () { $(".radio, .checkbox").checkboxradio({"destroy"}); }); </ script > </ center > </ body > </ html > |
Output:
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