Java Program for Stooge Sort
Last Updated :
13 Jun, 2022
The Stooge sort is a recursive sorting algorithm. It is defined as below (for ascending order sorting).
Step 1 : If value at index 0 is greater than
value at last index, swap them.
Step 2: Recursively,
a) Stooge sort the initial 2/3rd of the array.
b) Stooge sort the last 2/3rd of the array.
c) Stooge sort the initial 2/3rd again to confirm.
Java
import java.io.*;
public class stooge
{
static void stoogesort( int arr[], int l, int h)
{
if (l >= h)
return ;
if (arr[l] > arr[h])
{
int t = arr[l];
arr[l] = arr[h];
arr[h] = t;
}
if (h-l+ 1 > 2 )
{
int t = (h-l+ 1 ) / 3 ;
stoogesort(arr, l, h-t);
stoogesort(arr, l+t, h);
stoogesort(arr, l, h-t);
}
}
public static void main(String args[])
{
int arr[] = { 2 , 4 , 5 , 3 , 1 };
int n = arr.length;
stoogesort(arr, 0 , n- 1 );
for ( int i= 0 ; i < n; i++)
System.out.print(arr[i] + " " );
}
}
|
Output:
1 2 3 4 5
Time Complexity:
The running time complexity of stooge sort can be written as,
T(n) = 3T(3n/2) + O(1)
Solution of above recurrence is O(n(log3/log1.5)) = O(n2.709), hence it is slower than even bubble sort(n2).
Auxiliary Space: O(n)
Please refer complete article on Stooge Sort for more details!
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