# Find Nth term of the series 1, 8, 54, 384…

Given a number N. The task is to write a program to find the Nth term in the below series:

`1, 8, 54, 384...`

Examples:

```Input : 3
Output : 54
For N = 3
Nth term = ( 3*3) * 3!
= 54

Input : 2
Output : 8
```

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

On observing carefully, the Nth term in the above series can be generalized as:

`Nth term = ( N*N ) * ( N! )`

Below is the implementation of the above approach:

## C++

 `// CPP program to find N-th term of the series: ` `// 1, 8, 54, 384... ` `#include ` `using` `namespace` `std; ` ` `  `// calculate factorial of N ` `int` `fact(``int` `N) ` `{ ` `    ``int` `i, product = 1; ` `    ``for` `(i = 1; i <= N; i++) ` `        ``product = product * i; ` `    ``return` `product; ` `} ` ` `  `// calculate Nth term of series ` `int` `nthTerm(``int` `N) ` `{ ` `    ``return` `(N * N) * fact(N); ` `} ` ` `  `// Driver Function ` `int` `main() ` `{ ` `    ``int` `N = 4; ` ` `  `    ``cout << nthTerm(N); ` ` `  `    ``return` `0; ` `} `

## Java

 `// Java program to find N-th term of the series: ` `// 1, 8, 54, 384... ` ` `  `import` `java.io.*; ` ` `  `// Main class for main method ` `class` `GFG { ` `    ``public` `static` `int` `fact(``int` `N) ` `    ``{ ` `        ``int` `i, product = ``1``; ` `        ``// Calculate factorial of N ` `        ``for` `(i = ``1``; i <= N; i++) ` `            ``product = product * i; ` `        ``return` `product; ` `    ``} ` `    ``public` `static` `int` `nthTerm(``int` `N) ` `    ``{ ` `        ``// By using above formula ` `        ``return` `(N * N) * fact(N); ` `    ``} ` ` `  `    ``public` `static` `void` `main(String[] args) ` `    ``{ ` `        ``int` `N = ``4``; ``// 4th term is 384 ` ` `  `        ``System.out.println(nthTerm(N)); ` `    ``} ` `} `

## Python 3

 `# Python 3 program to find  ` `# N-th term of the series: ` `# 1, 8, 54, 384... ` ` `  `# calculate factorial of N ` `def` `fact(N): ` `     `  `    ``product ``=` `1` `    ``for` `i ``in` `range``(``1``, N ``+` `1``): ` `        ``product ``=` `product ``*` `i ` `    ``return` `product ` ` `  `# calculate Nth term of series ` `def` `nthTerm(N): ` `    ``return` `(N ``*` `N) ``*` `fact(N) ` ` `  `# Driver Code ` `if` `__name__ ``=``=``"__main__"``: ` `    ``N ``=` `4` `    ``print``(nthTerm(N)) ` ` `  `# This code is contributed ` `# by ChitraNayal `

## C#

 `// C# program to find N-th  ` `// term of the series: ` `// 1, 8, 54, 384... ` `using` `System; ` ` `  `class` `GFG  ` `{ ` `public` `static` `int` `fact(``int` `N) ` `{ ` `    ``int` `i, product = 1; ` `     `  `    ``// Calculate factorial of N ` `    ``for` `(i = 1; i <= N; i++) ` `        ``product = product * i; ` `    ``return` `product; ` `} ` ` `  `public` `static` `int` `nthTerm(``int` `N) ` `{ ` `    ``// By using above formula ` `    ``return` `(N * N) * fact(N); ` `} ` ` `  `// Driver Code ` `public` `static` `void` `Main(String[] args) ` `{ ` `    ``int` `N = 4; ``// 4th term is 384 ` ` `  `    ``Console.WriteLine(nthTerm(N)); ` `} ` `} ` ` `  `// This code is contributed  ` `// by Kirti_Mangal `

## PHP

 ` `

Output:

```384
```

Time Complexity: O(N)

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Improved By : Kirti_Mangal, chitranayal