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Draw a circle without floating point arithmetic

  • Difficulty Level : Hard
  • Last Updated : 22 Jul, 2021

Given a radius of a circle, draw the circle without using floating point arithmetic.
Following program uses a simple concept. Let the radius of the circle be r. Consider a square of size (2r+1)*(2r+1) around the circle to be drawn. Now walk through every point inside the square. For every every point (x,y), if (x, y) lies inside the circle (or x^2+ y^2 < r^2), then print it, otherwise print space.
 

C++




// C++ code to demonstrate to draw
// circle without floating
// point arithmetic
#include <stdio.h>
 
void drawCircle(int r)
{
    // Consider a rectangle of size N*N
    int N = 2*r+1;
 
    int x, y;  // Coordinates inside the rectangle
 
    // Draw a square of size N*N.
    for (int i = 0; i < N; i++)
    {
        for (int j = 0; j < N; j++)
        {
            // Start from the left most corner point
            x = i-r;
            y = j-r;
 
            // If this point is inside the circle, print it
            if (x*x + y*y <= r*r+1 )
                printf(".");
            else // If outside the circle, print space
                printf(" ");
            printf(" ");
        }
        printf("\n");
    }
}
 
// Driver Program to test above function
int  main()
{
    drawCircle(8);
    return 0;
}

Java




// Java code to demonstrate to draw
// circle without floating
// point arithmetic
 
class GFG
{
static void drawCircle(int r)
{
    // Consider a rectangle of size N*N
    int N = 2*r+1;
 
    int x, y; // Coordinates inside the rectangle
 
    // Draw a square of size N*N.
    for (int i = 0; i < N; i++)
    {
        for (int j = 0; j < N; j++)
        {
            // Start from the left most corner point
            x = i-r;
            y = j-r;
 
            // If this point is inside the circle, print it
            if (x*x + y*y <= r*r+1 )
                System.out.print(".");
            else
                // If outside the circle, print space
                System.out.print(" ");
 
            System.out.print(" ");
        }
 
        System.out.println();
    }
}
 
// Driver Program to test above function
public static void main(String arg[])
{
    drawCircle(8);
}
}
 
// This code is contributed
// by Anant Agarwal.

Python3




# Python3 code to demonstrate to draw
# circle without floating
# point arithmetic
 
def drawCircle(r):
 
    # Consider a rectangle of size N*N
    N = 2 * r + 1
 
    # Draw a square of size N*N.
    for i in range(N):
        for j in range(N):
 
            # Start from the left most corner point
            x = i - r
            y = j - r
 
            # If this point is inside the circle,
            # print it
            if x * x + y * y <= r * r + 1:
                print(".", end = " ")
                 
            # If outside the circle, print space
            else:
                print(" ", end = " ")
        print()
 
# Driver Code
if __name__ == "__main__":
    drawCircle(8)
 
# This code is contributed
# by vibhu4agarwal

C#




// C# code to demonstrate to draw
// circle without floating
// point arithmetic
using System;
 
public class GFG{
    static void drawCircle(int r)
{
    // Consider a rectangle of size N*N
    int N = 2*r+1;
 
    int x, y; // Coordinates inside the rectangle
 
    // Draw a square of size N*N.
    for (int i = 0; i < N; i++)
    {
        for (int j = 0; j < N; j++)
        {
            // Start from the left most corner point
            x = i-r;
            y = j-r;
 
            // If this point is inside the circle, print it
            if (x*x + y*y <= r*r+1 )
                Console.Write(".");
            else
                // If outside the circle, print space
                Console.Write(" ");
 
            Console.Write(" ");
        }
 
        Console.WriteLine();
    }
}
 
// Driver Program to test above function
    static public void Main (){
        drawCircle(8);
     
      
    }
// This code is contributed
// by ajit.
}

PHP




<?php
// PHP code to demonstrate to draw circle
// without floating point arithmetic
 
function drawCircle($r)
{
    // Consider a rectangle of size N*N
    $N = 2 * $r + 1;
 
    $y; // Coordinates inside the rectangle
 
    // Draw a square of size N*N.
    for ($i = 0; $i < $N; $i++)
    {
        for ( $j = 0; $j < $N; $j++)
        {
            // Start from the left most
            // corner point
            $x = $i - $r;
            $y = $j - $r;
 
            // If this point is inside the
            // circle, print it
            if ($x * $x + $y * $y <= $r * $r + 1)
                echo (".");
            else // If outside the circle,
                 // print space
                echo (" ");
            echo (" ");
        }
    echo "\n";
    }
}
 
// Driver Code
drawCircle(8);
 
// This code is contributed by akt_mit
?>

Javascript




<script>
 
function drawCircle(r)
{
    // Consider a rectangle of size N*N
    let N = 2*r+1;
   
    let x, y; // Coordinates inside the rectangle
   
    // Draw a square of size N*N.
    for (let i = 0; i < N; i++)
    {
        for (let j = 0; j < N; j++)
        {
            // Start from the left most corner point
            x = i - r;
            y = j - r;
   
            // If this point is inside the circle, print it
            if (x * x + y * y <= r * r + 1 )
                document.write(".");
            else
                // If outside the circle, print space
                document.write("  ");
   
            document.write("  ");
        }
   
        document.write("<br>");
    }
}
 
drawCircle(8);
// This code is contributed by avanitrachhadiya2155
</script>

Output: 
 

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