Check whether the given floating point number is a palindrome

Given a floating point number N, the task is to check whether it is palindrome or not.

Input: N = 123.321
Output: Yes

Input: N = 122.1
Output: Yes



Approach:

  • First convert the given floating point number into a character array.
  • Initialize the low to first index and high to last index.
  • While low < high:
    • If character at low is not equal to the character at high then exit and print “No”.
    • If character at low is equal to the character at high then continue after incrementing low and decrementing high..
  • If the above loop completes successfully then print “Yes”.

Below is the implementation of the above approach:

C++

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// C++ implementation of the approach
#include <bits/stdc++.h>
using namespace std;
  
// Function that returns true if num is palindrome
bool isPalindrome(float num)
{
      
    // Convert the given floating point number
    // into a string
    stringstream ss; 
    ss << num; 
    string s; 
    ss >> s; 
      
    // Pointers pointing to the first and
    // the last character of the string
    int low = 0;
    int high = s.size() - 1;
  
    while (low < high)
    {
  
        // Not a palindrome
        if (s[low] != s[high])
            return false;
  
        // Update the pointers
        low++;
        high--;
    }
    return true;
}
  
// Driver code
int main()
{
    float n = 123.321f;
  
    if (isPalindrome(n))
        cout << "Yes";
    else
        cout << "No";
  
    return 0;
}
  
// This code is contributed by Rajput-Ji

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Java

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// Java implementation of the approach
public class GFG {
  
    // Function that returns true if num is palindrome
    public static boolean isPalindrome(float num)
    {
  
        // Convert the given floating point number
        // into a string
        String s = String.valueOf(num);
  
        // Pointers pointing to the first and
        // the last character of the string
        int low = 0;
        int high = s.length() - 1;
  
        while (low < high) {
  
            // Not a palindrome
            if (s.charAt(low) != s.charAt(high))
                return false;
  
            // Update the pointers
            low++;
            high--;
        }
  
        return true;
    }
  
    // Driver code
    public static void main(String args[])
    {
  
        float n = 123.321f;
  
        if (isPalindrome(n))
            System.out.print("Yes");
  
        else
            System.out.print("No");
    }
}

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Python3

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# Python3 implementation of the approach 
  
# Function that returns true if num is palindrome 
def isPalindrome(num) : 
  
    # Convert the given floating point number 
    # into a string 
    s = str(num) 
      
    # Pointers pointing to the first and 
    # the last character of the string 
    low = 0
    high = len(s) - 1
  
    while (low < high): 
      
        # Not a palindrome 
        if (s[low] != s[high]): 
            return False
  
        # Update the pointers 
        low += 1
        high -= 1
      
    return True
  
# Driver code 
n = 123.321
  
if (isPalindrome(n)): 
    print("Yes"
else
    print("No"
  
# This code is contributed by ihritik 

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C#

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// C# implementation of the approach 
using System;
  
class GFG 
  
    // Function that returns true 
    // if num is palindrome 
    public static bool isPalindrome(float num) 
    
  
        // Convert the given floating point number 
        // into a string 
        string s = num.ToString(); 
  
        // Pointers pointing to the first and 
        // the last character of the string 
        int low = 0; 
        int high = s.Length - 1; 
  
        while (low < high) 
        
  
            // Not a palindrome 
            if (s[low] != s[high]) 
                return false
  
            // Update the pointers 
            low++; 
            high--; 
        
        return true
    
  
    // Driver code 
    public static void Main() 
    
        float n = 123.321f; 
  
        if (isPalindrome(n)) 
            Console.WriteLine("Yes"); 
  
        else
            Console.WriteLine("No"); 
    
}
  
// This code is contributed by AnkitRai01

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Output:

Yes


My Personal Notes arrow_drop_up

Talk is cheap Show me the code -)

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Improved By : AnkitRai01, Rajput-Ji, ihritik