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D3.js line.curve() method
  • Last Updated : 19 Aug, 2020

The d3.line.curve() method is used to give a curve to our line. D3.js provides several curve factories that can be used to give different curves.

Syntax:

d3.line.curve(curve_factory);

Parameters:

  • curve_factory: type of curve to be given to the line.

Return Value: This method has no return value.

Example 1: In this example, we will use the curveBasis curve factory.






<!DOCTYPE html>
<html>
<meta charset="utf-8">
<head>
  <title>d3.line.curve()</title>
</head>
<script src=
</script>
  
<body>
    <h1 style="text-align: center; 
        color: green;">GeeksforGeeks</h1>
  <center>
    <svg id="gfg" width="200" height="200"></svg>
</center>
  <script>
var points = [
  {xpoint: 25,  ypoint: 150},
  {xpoint: 75,  ypoint: 85},
  {xpoint: 100, ypoint: 115},
  {xpoint: 175, ypoint: 25}];
  
var Gen = d3.line()
  .x((p) => p.xpoint)
  .y((p) => p.ypoint)
  .curve(d3.curveBasis);
    
d3.select("#gfg")
  .append("path")
  .attr("d", Gen(points))
  .attr("fill", "none")
  .attr("stroke", "green");
  
</script>
</body>
</html>

Output:

Example 2: In this example, we will use the curveCardinal curve factory.




<!DOCTYPE html>
<html>
<meta charset="utf-8">
<head>
  <title>d3.line.curve()</title>
</head>
<script src=
</script>
  
<body>
    <h1 style="text-align: center; 
               color: green;">
         GeeksforGeeks
    </h1>
  <center>
    <svg id="gfg" width="200" 
         height="200">
    </svg>
</center>
  <script>
var points = [
  {xpoint: 25,  ypoint: 150},
  {xpoint: 75,  ypoint: 85},
  {xpoint: 100, ypoint: 115},
  {xpoint: 175, ypoint: 25}];
  
var Gen = d3.line()
  .x((p) => p.xpoint)
  .y((p) => p.ypoint)
  .curve(d3.curveCardinal);
  
d3.select("#gfg")
  .append("path")
  .attr("d", Gen(points))
  .attr("fill", "none")
  .attr("stroke", "green");
  
</script>
</body>
</html>

Output:

My Personal Notes arrow_drop_up
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