C++ Program for GCD of more than two (or array) numbers

The GCD of three or more numbers equals the product of the prime factors common to all the numbers, but it can also be calculated by repeatedly taking the GCDs of pairs of numbers.

gcd(a, b, c) = gcd(a, gcd(b, c)) 
             = gcd(gcd(a, b), c) 
             = gcd(gcd(a, c), b)

// C++ program to find GCD of two or 
// more numbers 
#include <bits/stdc++.h> 
using namespace std; 
  
// Function to return gcd of a and b 
int gcd(int a, int b) 
{ 
    if (a == 0) 
        return b; 
    return gcd(b % a, a); 
} 
  
// Function to find gcd of array of 
// numbers 
int findGCD(int arr[], int n) 
{ 
    int result = arr[0]; 
    for (int i = 1; i < n; i++) 
        result = gcd(arr[i], result); 
  
    return result; 
} 
  
// Driven code 
int main() 
{ 
    int arr[] = { 2, 4, 6, 8, 16 }; 
    int n = sizeof(arr) / sizeof(arr[0]); 
    cout << findGCD(arr, n) << endl; 
    return 0; 
} 

Output:

Please refer complete article on GCD of more than two (or array) numbers for more details!

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