Count number of even and odd elements in an array

For the given array of integers, count even and odd elements.

Examples:

Input : int arr[5] = {2, 3, 4, 5, 6}
Output : Number of even elements = 3    
         Number of odd elements = 2  

Input : int arr[5] = {22, 32, 42, 52, 62}
Output : Number of even elements = 5  
         Number of odd elements = 0



Simple approach: A number is said to be Even if it is completely divisible by 2. A number is said to be Odd if it is leaves 1 as remainder on dividing by 2.

Other approach: We can also check if a number is odd by doing AND of 1 and that digit, if the result comes out to be 1 then the number is odd otherwise even.

Here, we will check if a number is odd , then we will increment the odd
counter otherwise we will increment the even counter.

C++

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// CPP program to count number of even
// and odd elements in an array
#include<iostream>
using namespace std;
  
void CountingEvenOdd(int arr[], int arr_size)
{
    int even_count = 0;             
    int odd_count = 0;             
          
    // loop to read all the values in the array
    for(int i = 0 ; i < arr_size ; i++) 
    {
        // checking if a number is completely
        // divisible by 2
        if (arr[i] & 1 == 1)
            odd_count ++ ;         
        else                     
            even_count ++ ;         
    }
  
    cout << "Number of even elements = " << even_count 
         << "\nNumber of odd elements = " << odd_count ;         
}
  
// Driver Code
int main()
{
    int arr[] = {2, 3, 4, 5, 6};
    int n = sizeof(arr) / sizeof(arr[0]);
    CouningEvenOdd(arr, n);

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Java

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// java program to count number of even
// and odd elements in an array
import java.io.*;
  
class GFG {
  
    static void CountingEvenOdd(int arr[],
                              int arr_size)
    {
        int even_count = 0;         
        int odd_count = 0;         
              
        // loop to read all the values in
        // the array
        for(int i = 0 ; i < arr_size ; i++) 
        {
            // checking if a number is 
            // completely divisible by 2
            if ((arr[i] & 1) == 1)
                odd_count ++ ;     
            else                
                even_count ++ ;     
        }
      
        System.out.println( "Number of even"
               + " elements = " + even_count 
               + " Number of odd elements = "
                              + odd_count) ;     
    }
      
    // Driver Code
    public static void main (String[] args) 
    {
        int arr[] = {2, 3, 4, 5, 6};
        int n = arr.length;
        CountingEvenOdd(arr, n);
    }
}
  
// This code is Contributed by anuj_67.

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Python3

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# Python3 program to count number of 
# even and odd elements in an array 
def CountingEvenOdd(arr, arr_size): 
    even_count = 0            
    odd_count = 0            
          
    # loop to read all the values 
    # in the array 
    for i in range(arr_size): 
          
        # checking if a number is 
        # completely divisible by 2 
        if (arr[i] & 1 == 1): 
            odd_count += 1        
        else:                     
            even_count += 1
  
    print("Number of even elements = ",
                            even_count)
    print("Number of odd elements = "
                             odd_count) 
                      
# Driver Code
arr = [2, 3, 4, 5, 6
n = len(arr) 
CountingEvenOdd(arr, n)
  
# This code is contributed by sahishelangia

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C#

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// C# program to count number of even
// and odd elements in an array
using System;
  
class GFG {
  
    static void CountingEvenOdd(int []arr,
                            int arr_size)
    {
        int even_count = 0;         
        int odd_count = 0;         
              
        // loop to read all the values in
        // the array
        for(int i = 0 ; i < arr_size ; i++) 
        {
            // checking if a number is 
            // completely divisible by 2
            if ((arr[i] & 1) == 1)
                odd_count ++ ;     
            else            
                even_count ++ ;     
        }
      
        Console.WriteLine( "Number of even"
            + " elements = " + even_count 
            + " Number of odd elements = "
                            + odd_count) ;     
    }
      
    // Driver Code
    public static void Main () 
    {
        int []arr = {2, 3, 4, 5, 6};
        int n = arr.Length;
        CountingEvenOdd(arr, n);
    }
}
  
// This code is Contributed by anuj_67.

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PHP

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<?php
// PHP program to count number of even
// and odd elements in an array
  
function CountingEvenOdd( $arr, $arr_size)
{
    $even_count = 0;         
    $odd_count = 0;             
          
    // loop to read all the values in
    // the array
    for( $i = 0 ; $i < $arr_size ; $i++) 
    {
        // checking if a number is 
        // completely divisible by 2
        if ($arr[$i] & 1 == 1)
            $odd_count ++ ;     
        else                
            $even_count ++ ;         
    }
  
    echo "Number of even elements = " ,
        $even_count," Number of odd " ,
            "elements = " ,$odd_count ;     
}
  
// Driver Code
    $arr = array(2, 3, 4, 5, 6);
    $n = count($arr);
    CountingEvenOdd($arr, $n);
  
// This code is Contributed by anuj_67.
?>

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Output:

Number of even elements = 3   Number of odd elements = 2


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