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# Check whether triangle is valid or not if three points are given

Given coordinates of three points in a plane P1, P2 and P3, the task is to check if the three points form a triangle or not
Examples:

Input: P1 = (1, 5), P2 = (2, 5), P3 = (4, 6)
Output: Yes
Input: P1 = (1, 1), P2 = (1, 4), P3 = (1, 5)
Output: No

Approach: The key observation in the problem is three points form a triangle only when they don’t lie on the straight line, that is an area formed by the triangle of these three points is not equal to zero.

The above formula is derived from shoelace formula.
So we will check if the area formed by the triangle is zero or not.
Below is the implementation of the above approach:

## C++

 // C++ implementation to check// if three points form a triangle #include using namespace std; // Function to check if three// points make a trianglevoid checkTriangle(int x1, int y1, int x2,                   int y2, int x3, int y3){     // Calculation the area of    // triangle. We have skipped    // multiplication with 0.5    // to avoid floating point    // computations    int a = x1 * (y2 - y3)            + x2 * (y3 - y1)            + x3 * (y1 - y2);     // Condition to check if    // area is not equal to 0    if (a == 0)        cout << "No";    else        cout << "Yes";} // Driver Codeint main(){    int x1 = 1, x2 = 2, x3 = 3,        y1 = 1, y2 = 2, y3 = 3;    checkTriangle(x1, y1, x2,                  y2, x3, y3);    return 0;}

## Java

 // Java implementation to check// if three points form a triangleimport java.io.*;import java.util.*; class GFG {     // Function to check if three// points make a trianglestatic void checkTriangle(int x1, int y1,                          int x2, int y2,                          int x3, int y3){     // Calculation the area of    // triangle. We have skipped    // multiplication with 0.5    // to avoid floating point    // computations    int a = x1 * (y2 - y3) +            x2 * (y3 - y1) +            x3 * (y1 - y2);     // Condition to check if    // area is not equal to 0    if (a == 0)        System.out.println("No");    else        System.out.println("Yes");} // Driver codepublic static void main(String[] args){    int x1 = 1, y1 = 1,        x2 = 2, y2 = 2,        x3 = 3, y3 = 3;    checkTriangle(x1, y1, x2, y2, x3, y3);}} // This code is contributed by coder001

## Python3

 # Python3 implementation to check# if three points form a triangle # Function to check if three# points make a triangledef checkTriangle(x1, y1, x2, y2, x3, y3):         # Calculation the area of    # triangle. We have skipped    # multiplication with 0.5    # to avoid floating point    # computations    a = (x1 * (y2 - y3) +         x2 * (y3 - y1) +         x3 * (y1 - y2))             # Condition to check if    # area is not equal to 0    if a == 0:        print('No')    else:        print('Yes')         # Driver codeif __name__=='__main__':         (x1, x2, x3) = (1, 2, 3)    (y1, y2, y3) = (1, 2, 3)         checkTriangle(x1, y1, x2, y2, x3, y3)     # This code is contributed by rutvik_56

## C#

 // C# implementation to check// if three points form a triangleusing System; class GFG {     // Function to check if three// points make a trianglestatic void checkTriangle(int x1, int y1,                          int x2, int y2,                          int x3, int y3){    // Calculation the area of    // triangle. We have skipped    // multiplication with 0.5    // to avoid floating point    // computations    int a = x1 * (y2 - y3) +            x2 * (y3 - y1) +            x3 * (y1 - y2);     // Condition to check if    // area is not equal to 0    if (a == 0)        Console.WriteLine("No");    else        Console.WriteLine("Yes");} // Driver codepublic static void Main(){    int x1 = 1, y1 = 1,        x2 = 2, y2 = 2,        x3 = 3, y3 = 3;             checkTriangle(x1, y1, x2, y2, x3, y3);}} //This code is contributed by AbhiThakur

## Javascript



Output:

No

Time Complexity: O(1)

Auxiliary Space : O(1)

#### Approach#2: Using the Triangle Inequality Theorem

One way to check if a triangle is valid is to use the triangle inequality theorem. According to this theorem, the sum of the lengths of any two sides of a triangle must be greater than the length of the third side. Therefore, if we calculate the lengths of all three sides of the triangle and check if this condition is satisfied, we can determine if the triangle is valid or not.

#### Algorithm

1. Define a function valid_triangle(p1, p2, p3) that takes the three points as input.
2. Calculate the lengths of all three sides of the triangle using the distance formula.
3. Check if the sum of the lengths of any two sides is greater than the length of the third side.
4. If this condition is satisfied for all three combinations of sides, the triangle is valid; otherwise, it is invalid.

## Java

 // java code additionimport java.io.*; public class Main {    // Find the distance between two points.    public static double distance(double[] p1, double[] p2) {        return Math.sqrt(Math.pow(p2[0] - p1[0], 2) + Math.pow(p2[1] - p1[1], 2));    }     // checks whether the triangle is valid,    // by checking if sum of two sides is greater then the third side.    public static boolean validTriangle(double[] p1, double[] p2, double[] p3) {        double d1 = distance(p1, p2);        double d2 = distance(p2, p3);        double d3 = distance(p3, p1);        return d1 + d2 > d3 && d2 + d3 > d1 && d3 + d1 > d2;    }     // Example usage    public static void main(String[] args) {        double[] P1 = {1, 5};        double[] P2 = {2, 5};        double[] P3 = {4, 6};        System.out.println(validTriangle(P1, P2, P3)); // Output: true         double[] P4 = {1, 1};        double[] P5 = {1, 4};        double[] P6 = {1, 5};        System.out.println(validTriangle(P4, P5, P6)); // Output: false    }} // The code is contributed by Arushi Goel.

## Python3

 from math import sqrt def distance(p1, p2):    return sqrt((p2[0] - p1[0])**2 + (p2[1] - p1[1])**2) def valid_triangle(p1, p2, p3):    d1 = distance(p1, p2)    d2 = distance(p2, p3)    d3 = distance(p3, p1)    return d1 + d2 > d3 and d2 + d3 > d1 and d3 + d1 > d2 # Example usageP1 = (1, 5)P2 = (2, 5)P3 = (4, 6)print(valid_triangle(P1, P2, P3)) # Output: True P1 = (1, 1)P2 = (1, 4)P3 = (1, 5)print(valid_triangle(P1, P2, P3)) # Output: False

## Javascript

 // javascript code addition // Find the distance between two points.function distance(p1, p2) {  return Math.sqrt((p2[0] - p1[0]) ** 2 + (p2[1] - p1[1]) ** 2);} // checks whether the triangle is valid,// by checking if sum of two sides is greater then the third side.function validTriangle(p1, p2, p3) {  const d1 = distance(p1, p2);  const d2 = distance(p2, p3);  const d3 = distance(p3, p1);  return d1 + d2 > d3 && d2 + d3 > d1 && d3 + d1 > d2;} // Example usageconst P1 = [1, 5];const P2 = [2, 5];const P3 = [4, 6];console.log(validTriangle(P1, P2, P3)); // Output: true const P4 = [1, 1];const P5 = [1, 4];const P6 = [1, 5];console.log(validTriangle(P4, P5, P6)); // Output: false // The code is contributed by Arushi Goel.

Output

True
False

Time Complexity: O(1)
Space Complexity: O(1)