Given a non-negative number **n** and two values **l** and **r**. The problem is to check whether all the bits are set or not in the range **l** to **r** in the binary representation of **n**. **Constraint:** 1 <= l <= r <= number of bits in the binary representation of **n**.

Examples:

Input : n = 22, l = 2, r = 3 Output : Yes (22)_{10}= (10110)_{2}The bits in the range2to3are all set. Input : n = 47, l = 2, r = 5 Output : No (47)_{10}= (101111)_{2}The bits in the range2to5are all not set.

**Approach:** Following are the steps:

- Calculate
**num**= ((1 << r) – 1) ^ ((1 << (l-1)) – 1). This will produce a number**num**having**r**number of bits and bits in the range**l**to**r**are the only set bits. - Calculate
**new_num**= n & num. - If num == new_num, return “Yes” (all bits are set in the given range).
- Else return “No” (all bits are not set in the given range).

## C++

`// C++ implementation to check whether all the bits` `// are set in the given range or not` `#include <bits/stdc++.h>` `using` `namespace` `std;` `// function to check whether all the bits` `// are set in the given range or not` `string allBitsSetInTheGivenRange(unsigned ` `int` `n,` ` ` `unsigned ` `int` `l, unsigned ` `int` `r)` `{` ` ` `// calculating a number 'num' having 'r'` ` ` `// number of bits and bits in the range l` ` ` `// to r are the only set bits` ` ` `int` `num = ((1 << r) - 1) ^ ((1 << (l - 1)) - 1);` ` ` ` ` `// new number which will only have one or more` ` ` `// set bits in the range l to r and nowhere else` ` ` `int` `new_num = n & num;` ` ` ` ` `// if both are equal, then all bits are set` ` ` `// in the given range` ` ` `if` `(num == new_num)` ` ` `return` `"Yes"` `;` ` ` ` ` `// else all bits are not set ` ` ` `return` `"No"` `; ` `}` `// Driver program to test above` `int` `main()` `{` ` ` `unsigned ` `int` `n = 22;` ` ` `unsigned ` `int` `l = 2, r = 3;` ` ` `cout << allBitsSetInTheGivenRange(n, l, r);` ` ` `return` `0;` `}` |

## Java

`// Java implementation to check whether all` `// the bits are set in the given range or not` `class` `GFG {` ` ` ` ` `// function to check whether all the bits` ` ` `// are set in the given range or not` ` ` `static` `String allBitsSetInTheGivenRange(` `int` `n,` ` ` `int` `l,` `int` `r)` ` ` `{` ` ` ` ` `// calculating a number 'num' having 'r'` ` ` `// number of bits and bits in the range` ` ` `// l to r are the only set bits` ` ` `int` `num = ((` `1` `<< r) - ` `1` `) ^ ((` `1` `<<` ` ` `(l - ` `1` `)) - ` `1` `);` ` ` ` ` `// new number which will only have one` ` ` `// or more set bits in the range l to r` ` ` `// and nowhere else` ` ` `int` `new_num = n & num;` ` ` ` ` `// if both are equal, then all bits are` ` ` `// set in the given range` ` ` `if` `(num == new_num)` ` ` `return` `"Yes"` `;` ` ` ` ` `// else all bits are not set` ` ` `return` `"No"` `;` ` ` `}` ` ` ` ` `//Driver code` ` ` `public` `static` `void` `main (String[] args)` ` ` `{` ` ` `int` `n = ` `22` `;` ` ` `int` `l = ` `2` `, r = ` `3` `;` ` ` ` ` `System.out.print(allBitsSetInTheGivenRange(` ` ` `n, l, r));` ` ` `}` `}` `// This code is contributed by Anant Agarwal.` |

## Python3

`# Python3 implementation to check` `# whether all the bits are set in` `# the given range or not` `# Function to check whether all the bits` `# are set in the given range or not` `def` `allBitsSetInTheGivenRange(n, l, r):` ` ` `# calculating a number 'num' having 'r'` ` ` `# number of bits and bits in the range l` ` ` `# to r are the only set bits` ` ` `num ` `=` `((` `1` `<< r) ` `-` `1` `) ^ ((` `1` `<< (l ` `-` `1` `)) ` `-` `1` `)` ` ` ` ` `# new number which will only have` ` ` `# one or more set bits in the range` ` ` `# l to r and nowhere else` ` ` `new_num ` `=` `n & num` ` ` ` ` `# if both are equal, then all bits` ` ` `# are set in the given range` ` ` `if` `(num ` `=` `=` `new_num):` ` ` `return` `"Yes"` ` ` ` ` `# else all bits are not set` ` ` `return` `"No"` `# Driver code` `n, l, r ` `=` `22` `, ` `2` `, ` `3` `print` `(allBitsSetInTheGivenRange(n, l, r))` `# This code is contributed by Anant Agarwal.` |

## C#

`// C# implementation to check whether all the bits` `// are set in the given range or not` `using` `System;` `class` `GFG` `{` ` ` `// function to check whether all the bits` ` ` `// are set in the given range or not` ` ` `static` `String allBitsSetInTheGivenRange(` `int` `n,` ` ` `int` `l,` `int` `r)` ` ` `{` ` ` `// calculating a number 'num' having 'r'` ` ` `// number of bits and bits in the range l` ` ` `// to r are the only set bits` ` ` `int` `num = ((1 << r) - 1) ^ ((1 << (l - 1)) - 1);` ` ` ` ` `// new number which will only have one or more` ` ` `// set bits in the range l to r and nowhere else` ` ` `int` `new_num = n & num;` ` ` ` ` `// if both are equal, then all bits are set` ` ` `// in the given range` ` ` `if` `(num == new_num)` ` ` `return` `"Yes"` `;` ` ` ` ` `// else all bits are not set ` ` ` `return` `"No"` `; ` ` ` `}` ` ` ` ` `//Driver code` ` ` `public` `static` `void` `Main ()` ` ` `{` ` ` `int` `n = 22;` ` ` `int` `l = 2, r = 3;` ` ` `Console.Write(allBitsSetInTheGivenRange(n, l, r));` ` ` `}` `}` `// This code is contributed by Anant Agarwal.` |

## PHP

`<?php` `// PHP implementation to check` `// whether all the bits are set` `// in the given range or not` `// function to check whether` `// all the bits are set in` `// the given range or not` `function` `allBitsSetInTheGivenRange(` `$n` `, ` `$l` `, ` `$r` `)` `{` ` ` ` ` `// Calculating a number` ` ` `// 'num' having 'r'` ` ` `// number of bits and` ` ` `// bits in the range l` ` ` `// to r are the only` ` ` `// set bits` ` ` `$num` `= ((1 << ` `$r` `) - 1) ^` ` ` `((1 << (` `$l` `- 1)) - 1);` ` ` ` ` `// new number which will` ` ` `// only have one or more` ` ` `// set bits in the range` ` ` `// l to r and nowhere else` ` ` `$new_num` `= ` `$n` `& ` `$num` `;` ` ` ` ` `// if both are equal,` ` ` `// then all bits are set` ` ` `// in the given range` ` ` `if` `(` `$num` `== ` `$new_num` `)` ` ` `return` `"Yes"` `;` ` ` ` ` `// else all bits` ` ` `// are not set` ` ` `return` `"No"` `;` `}` ` ` `// Driver Code` ` ` `$n` `= 22;` ` ` `$l` `= 2;` ` ` `$r` `= 3;` ` ` `echo` `allBitsSetInTheGivenRange(` `$n` `, ` `$l` `, ` `$r` `);` ` ` `// This code is contributed by Ajit` `?>` |

## Javascript

`<script>` `// javascript implementation to check whether all` `// the bits are set in the given range or not` ` ` `// function to check whether all the bits` `// are set in the given range or not` `function` `allBitsSetInTheGivenRange(n,l,r)` `{` ` ` ` ` `// calculating a number 'num' having 'r'` ` ` `// number of bits and bits in the range` ` ` `// l to r are the only set bits` ` ` `var` `num = ((1 << r) - 1) ^ ((1 <<` ` ` `(l - 1)) - 1);` ` ` ` ` `// new number which will only have one` ` ` `// or more set bits in the range l to r` ` ` `// and nowhere else` ` ` `var` `new_num = n & num;` ` ` ` ` `// if both are equal, then all bits are` ` ` `// set in the given range` ` ` `if` `(num == new_num)` ` ` `return` `"Yes"` `;` ` ` ` ` `// else all bits are not set` ` ` `return` `"No"` `;` `}` `// Driver code` `var` `n = 22;` `var` `l = 2, r = 3;` `document.write(allBitsSetInTheGivenRange(` ` ` `n, l, r));` `// This code contributed by Princi Singh` `</script>` |

Output:

Yes

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