Given a non-negative number n and two values l and r. The problem is to check whether all the bits are unset or not in the range l to r in the binary representation of n. The bits are numbered from right to left, i.e., the least significant bit is considered to be at first position.
Constraint: 1 <= l <= r <= number of bits in the binary representation of n.
Input : n = 17, l = 2, r = 4 Output : Yes (17)10 = (10001)2 The bits in the range 2 to 4 are all unset. Input : n = 39, l = 4, r = 6 Output : No (39)10 = (100111)2 The bits in the range 4 to 6 are all not unset.
Approach: Following are the steps:
- Calculate num = ((1 << r) – 1) ^ ((1 << (l-1)) – 1). This will produce a number num having r number of bits and bits in the range l to r are the only set bits.
- Calculate new_num = n & num.
- If new_num == 0, return “Yes” (all bits are unset in the given range).
- Else return “No” (all bits are not unset in the given range).
- Check whether all the bits are unset in the given range or not
- Unset bits in the given range
- Count unset bits in a range
- Python | Count unset bits in a range
- Check if a number has same number of set and unset bits
- Check whether all the bits are set in the given range
- Check if bits in range L to R of two numbers are complement of each other or not
- Check whether bits are in alternate pattern in the given range | Set-2
- Check whether bits are in alternate pattern in the given range
- Unset the last m bits
- Count unset bits of a number
- Count total unset bits in all the numbers from 1 to N
- Find the smallest number with n set and m unset bits
- Find the largest number with n set and m unset bits
- Check if bits of a number has count of consecutive set bits in increasing order
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Improved By : Smitha Dinesh Semwal