Check mirror in n-ary tree
Given two n-ary trees, the task is to check if they are the mirror of each other or not. Print “Yes” if they are the mirror of each other else “No”.
Input : Node = 3, Edges = 2 Edge 1 of first N-ary: 1 2 Edge 2 of first N-ary: 1 3 Edge 1 of second N-ary: 1 3 Edge 2 of second N-ary: 1 2 Output : Yes
Input : Node = 3, Edges = 2 Edge 1 of first N-ary: 1 2 Edge 2 of first N-ary: 1 3 Edge 1 of second N-ary: 1 2 Edge 2 of second N-ary: 1 3 Output : No
Approach 1: (Using Hashing)
The idea is to use an unordered map of stacks to check if given N-ary tree are mirror of each other or not.
Let the first n-ary tree be t1 and the second n-ary tree is t2. For each node in t1, push its connected node in their corresponding stack in the map. Now, for each node in t2, their connected node match with the top of the stack, then pop elements from the stack.
Otherwise, if the node does not match with the top of the stack then it means two trees are not mirror of each other.
Now, for each corresponding node do the following:
1. Iterate over map of stack Push all connected nodes of each node of first tree in map of stack. 2. Again iterate over map for each node of second tree For example : Let us take one node X of second tree For this node X , check in map which stack is used a = Top of that stack for node X present in second tree; b = Connected node of X in second tree if (a != b) return false; pop node X from stack.
Approach 2: (Using LinkedList):
The main approach is to use one list of stack and one list of queue to store to value of nodes given in the form of two arrays.
1. Initialize both the lists with empty stack and empty queues respectively. 2. Now, iterate over the lists Push all connected nodes of each node of first tree in list of stack and second tree list of queue. 3. Now iterate over the array and pop item from both stack and queue and check if they are same, if not same then return 0.
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