Given a number N, the task is to check if the all sub-numbers of this number have distinct digit product.
- An N digit number has N*(N+1)/2 sub-numbers. For example, all possible sub-numbers of 975 are 9, 7, 5, 97, 75, 975.
- Digit product of a number is product of its digits.
Input : N = 324 Output : YES Sub-numbers of 324 are 3, 2, 4, 32, 24 and 324 and digit products are 3, 2, 4, 6, 8 and 24 respectively. All the digit products are different. Input : N = 323 Output : NO Sub-numbers of 323 are 3, 2, 3, 32, 23 and 323 and digit products are 3, 2, 3, 6, 6 and 18 respectively. Digit products 3 and 6 have occurred twice.
- Make a digit array i.e., an array with its elements as digits of given number N.
- Now finding sub-numbers of N is similar to finding all possible subarrays of the digit array.
- Maintain a list of digit products of these subarrays.
- If any digit product has appeared more than once, print NO.
- Else print YES.
Below is the implementation of the above approach :
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- Longest subsequence such that adjacent elements have at least one common digit
- Longest subarray such that adjacent elements have at least one common digit | Set - 2
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