An interesting method to print reverse of a linked list

We are given a linked list, we need to print the linked list in reverse order.

Examples:

Input : list : 5-> 15-> 20-> 25 
Output : Reversed Linked list : 25-> 20-> 15-> 5

Input : list : 85-> 15-> 4-> 20 
Output : Reversed Linked list : 20-> 4-> 15-> 85

Input : list : 85
Output : Reversed Linked list : 85

For printing a list in reverse order, we have already discussed Iterative and Recursive Methods to Reverse.

In this post, an interesting method is discussed, that doesn’t require recursion and does no modifications to list. The function also visits every node of linked list only once.



Trick : Idea behind printing a list in reverse order without any recursive function or loop is to use Carriage return (“r”). For this, we should have knowledge of length of list. Now, we should print n-1 blanck space and then print 1st element then “r”, futher again n-2 blank space and 2nd node then “r” and so on..
Carriage return (“r”) : It commands a printer (cursor or the display of a system console), to move the position of the cursor to the first position on the same line.

C/C++

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// C program to print reverse of list
#include <stdio.h>
#include <stdlib.h>
   
/* Link list node */
struct Node {
    int data;
    struct Node* next;
};
   
/* Function to reverse the linked list */
void printReverse(struct Node** head_ref, int n)
{
    int j = 0;
    struct Node* current = *head_ref;
    while (current != NULL) {
   
        // For each node, print proper number
        // of spaces before printing it
        for (int i = 0; i < 2 * (n - j); i++)
            printf(" ");
   
        // use of carriage return to move back
        // and print.
        printf("%d\r", current->data);
   
        current = current->next;
        j++;
    }
}
   
/* Function to push a node */
void push(struct Node** head_ref, int new_data)
{
    struct Node* new_node = 
          (struct Node*)malloc(sizeof(struct Node));
   
    new_node->data = new_data;
    new_node->next = (*head_ref);
    (*head_ref) = new_node;
}
   
/* Function to print linked list and find its
   length */
int printList(struct Node* head)
{
    // i for finding length of list
    int i = 0;
    struct Node* temp = head;
    while (temp != NULL) {
        printf("%d  ", temp->data);
        temp = temp->next;
        i++;
    }
    return i;
}
   
/* Driver program to test above function*/
int main()
{
    /* Start with the empty list */
    struct Node* head = NULL;
    // list nodes are as 6 5 4 3 2 1
    push(&head, 1);
    push(&head, 2);
    push(&head, 3);
    push(&head, 4);
    push(&head, 5);
    push(&head, 6);
   
    printf("Given linked list:\n");
    // printlist print the list and
    // return the size of list
    int n = printList(head);
   
    // print reverse list with help
    // of carriage return function
    printf("\nReversed Linked list:\n");
    printReverse(&head, n);
    printf("\n");
    return 0;
}

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Java

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// Java program to print reverse of list
import java.io.*;
import java.util.*;
   
// Represents node of a linkedlist
class Node {
      int data;
      Node next;
      Node(int val)
      {
          data = val;
          next = null;
      }
}
   
public class GFG 
{
   
   /* Function to reverse the linked list */
   static void printReverse(Node head, int n)
   {
          int j = 0;
          Node current = head;
          while (current != null) {
              
             // For each node, print proper number 
             // of spaces before printing it 
             for (int i = 0; i < 2 * (n - j); i++)
                  System.out.print(" ");
  
             // use of carriage return to move back 
             // and print.
             System.out.print("\r" + current.data);
  
             current = current.next;
             j++; 
          }
   }
  
   /* Function to push a node */
   static Node push(Node head, int data) 
   {
          Node new_node = new Node(data);
          new_node.next = head;
          head = new_node;
  
          return head;
   }
  
   /* Function to print linked list and find its 
   length */
   static int printList(Node head)
   {
          // i for finding length of list 
          int i = 0;
          Node temp = head;
          while (temp != null)
          {
                 System.out.print(temp.data + " ");
                 temp = temp.next;
                 i++;
          }
  
          return i;
   }
  
   // Driver code
   public static void main(String args[])
   {
          /* Start with the empty list */
          Node head = null;
  
          // list nodes are as 6 5 4 3 2 1
          head = push(head, 1);
          head = push(head, 2);
          head = push(head, 3);
          head = push(head, 4);
          head = push(head, 5);
          head = push(head, 6);
  
          System.out.println("Given linked list: ");
            
          // printlist print the list and 
          // return the size of list 
          int n = printList(head); 
  
          // print reverse list with help 
          // of carriage return function
          System.out.println("Reversed Linked list: ");
          printReverse(head, n); 
          System.out.println();
  
   }
}
   
// This code is contributed by rachana soma

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C#

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// C# program to print reverse of list
using System;
    
// Represents node of a linkedlist
public class Node {
      public int data;
      public Node next;
      public Node(int val)
      {
          data = val;
          next = null;
      }
}
    
public class GFG
{
    
   /* Function to reverse the linked list */
   static void printReverse(Node head, int n)
   {
          int j = 0;
          Node current = head;
          while (current != null) {
               
             // For each node, print proper number 
             // of spaces before printing it 
             for (int i = 0; i < 2 * (n - j); i++)
                  Console.Write(" ");
  
             // use of carriage return to move back 
             // and print.
             Console.Write("\r" + current.data);
  
             current = current.next;
             j++; 
          }
   }
  
   /* Function to push a node */
   static Node push(Node head, int data) 
   {
          Node new_node = new Node(data);
          new_node.next = head;
          head = new_node;
  
          return head;
   }
  
   /* Function to print linked list and find its 
   length */
   static int printList(Node head)
   {
          // i for finding length of list 
          int i = 0;
          Node temp = head;
          while (temp != null)
          {
                 Console.Write(temp.data + " ");
                 temp = temp.next;
                 i++;
          }
  
          return i;
   }
    
   // Driver code
   public static void Main(String []args)
   {
      /* Start with the empty list */
      Node head = null;
  
      // list nodes are as 6 5 4 3 2 1
      head = push(head, 1);
      head = push(head, 2);
      head = push(head, 3);
      head = push(head, 4);
      head = push(head, 5);
      head = push(head, 6);
  
      Console.WriteLine("Given linked list: ");
      // printlist print the list and 
      // return the size of list 
      int n = printList(head); 
  
      // print reverse list with help 
      // of carriage return function
      Console.WriteLine("Reversed Linked list: ");
      printReverse(head, n); 
      Console.WriteLine();
   }
}
    
// This code is contributed by Arnab Kundu

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Python3

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# Python3 program to print reverse of list
   
# Link list node 
class Node:
    def __init__(self):
        self.data=  0
        self.next=None
   
# Function to reverse the linked list 
def printReverse( head_ref, n):
   
    j = 0
    current = head_ref
    while (current != None): 
        i = 0
          
        # For each node, print proper number
        # of spaces before printing it
        while ( i < 2 * (n - j) ):
            print(end=" ")
            i = i + 1
    
        # use of carriage return to move back
        # and print.
        print( current.data, end = "\r")
    
        current = current.next
        j = j + 1
       
 # Function to push a node 
def push( head_ref, new_data):
   
    new_node = Node() 
    
    new_node.data = new_data
    new_node.next = (head_ref)
    (head_ref) = new_node
    return head_ref;
    
# Function to print linked list and find its
#  length 
def printList( head):
   
    # i for finding length of list
    i = 0
    temp = head
    while (temp != None): 
        print( temp.data,end = " ")
        temp = temp.next
        i = i + 1
       
    return i
   
# Driver program to test above function
   
# Start with the empty list 
head = None
  
# list nodes are as 6 5 4 3 2 1
head = push(head, 1)
head = push(head, 2)
head = push(head, 3)
head = push(head, 4)
head = push(head, 5)
head = push(head, 6)
    
print("Given linked list:")
  
# printlist print the list and
# return the size of list
n = printList(head)
    
# print reverse list with help
# of carriage return function
print("\nReversed Linked list:")
printReverse(head, n)
print()
   
# This code is contributed by Arnab Kundu

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Output:

Given linked list:
6 5 4 3 2 1
Reversed Linked List:
1 2 3 4 5 6

Input and Output Illustration :
Input : 6 5 4 3 2 1
1st Iteration _ _ _ _ _ 6
2nd Iteration _ _ _ _ 5 6
3rd Iteration _ _ _ 4 5 6
4th Iteration _ _ 3 4 5 6
5th Iteration _ 2 3 4 5 6
Final Output 1 2 3 4 5 6

NOTE:Above program may not work on online compiler because they do not support anything like carriage return on their console.


Reference :

stackoverflow/Carriage return

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Improved By : rachana soma, andrew1234

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