Related Articles

# Print Doubly Linked list in Reverse Order

• Last Updated : 29 Jun, 2021

Given a doubly-linked list of positive integers. The task is to print the given doubly linked list data in reverse order.
Examples

```Input: List = 1 <=> 2 <=>  3 <=>  4 <=>  5
Output: 5  4  3  2  1

Input: 10 <=> 20 <=> 30 <=> 40
Output: 40  30  20  10```

Approach:

• Take a pointer to point to head of the doubly linked list.
• Now, start traversing through the linked list till the end.
• After reaching last node, start traversing in backward direction and simultaneously print the node->data.

Below is the implementation of the above approach:

## C++

 `// C++ Program to print doubly``// linked list in reverse order``#include ``using` `namespace` `std;` `// Doubly linked list node``struct` `Node {``    ``int` `data;``    ``struct` `Node* next;``    ``struct` `Node* prev;``};` `// Function to print nodes of Doubly``// Linked List in reverse order``void` `reversePrint(``struct` `Node** head_ref)``{``    ``struct` `Node* tail = *head_ref;` `    ``// Traversing till tail of the linked list``    ``while` `(tail->next != NULL) {``        ``tail = tail->next;``    ``}` `    ``// Traversing linked list from tail``    ``// and printing the node->data``    ``while` `(tail != *head_ref) {``        ``cout << tail->data << ``" "``;``        ``tail = tail->prev;``    ``}``    ``cout << tail->data << endl;``}` `/* UTILITY FUNCTIONS */``// Function to insert a node at the``// beginging of the Doubly Linked List``void` `push(``struct` `Node** head_ref, ``int` `new_data)``{``    ``// allocate node``    ``struct` `Node* new_node = (``struct` `Node*)``malloc``(``sizeof``(``struct` `Node));` `    ``// put in the data``    ``new_node->data = new_data;` `    ``// since we are adding at the beginning,``    ``// prev is always NULL``    ``new_node->prev = NULL;` `    ``// link the old list off the new node``    ``new_node->next = (*head_ref);` `    ``// change prev of head node to new node``    ``if` `((*head_ref) != NULL)``        ``(*head_ref)->prev = new_node;` `    ``// move the head to point to the new node``    ``(*head_ref) = new_node;``}` `// Driver Code``int` `main()``{``    ``// Start with the empty list``    ``struct` `Node* head = NULL;` `    ``// Let us create a sorted linked list``    ``// to test the functions``    ``// Created linked list will be 10->8->4->2``    ``push(&head, 2);``    ``push(&head, 4);``    ``push(&head, 8);``    ``push(&head, 10);` `    ``cout << ``"Linked List elements in reverse order : "` `<< endl;` `    ``reversePrint(&head);` `    ``return` `0;``}`

## Java

 `// Java Program to print doubly``// linked list in reverse order``class` `Sol``{` `// Doubly linked list node``static` `class` `Node``{``    ``int` `data;``    ``Node next;``    ``Node prev;``};` `// Function to print nodes of Doubly``// Linked List in reverse order``static` `void` `reversePrint( Node head_ref)``{``    ``Node tail = head_ref;` `    ``// Traversing till tail of the linked list``    ``while` `(tail.next != ``null``)``    ``{``        ``tail = tail.next;``    ``}` `    ``// Traversing linked list from tail``    ``// and printing the node.data``    ``while` `(tail != head_ref)``    ``{``        ``System.out.print( tail.data + ``" "``);``        ``tail = tail.prev;``    ``}``    ``System.out.println( tail.data );``}` `// UTILITY FUNCTIONS /``// Function to insert a node at the``// beginging of the Doubly Linked List``static` `Node push( Node head_ref, ``int` `new_data)``{``    ``// allocate node``    ``Node new_node = ``new` `Node();` `    ``// put in the data``    ``new_node.data = new_data;` `    ``// since we are adding at the beginning,``    ``// prev is always null``    ``new_node.prev = ``null``;` `    ``// link the old list off the new node``    ``new_node.next = (head_ref);` `    ``// change prev of head node to new node``    ``if` `((head_ref) != ``null``)``        ``(head_ref).prev = new_node;` `    ``// move the head to point to the new node``    ``(head_ref) = new_node;``    ``return` `head_ref;``}` `// Driver Code``public` `static` `void` `main(String args[])``{``    ``// Start with the empty list``    ``Node head = ``null``;` `    ``// Let us create a sorted linked list``    ``// to test the functions``    ``// Created linked list will be 10.8.4.2``    ``head = push(head, ``2``);``    ``head = push(head, ``4``);``    ``head = push(head, ``8``);``    ``head = push(head, ``10``);` `    ``System.out.print( ``"Linked List elements in reverse order : "` `);` `    ``reversePrint(head);``}``}` `// This code is contributed by Arnab Kundu`

## Python3

 `# Python3 Program to print doubly``# linked list in reverse order``import` `math` `# Doubly linked list node``class` `Node:``    ``def` `__init__(``self``, data):``        ``self``.data ``=` `data``        ``self``.``next` `=` `None` `# Function to print nodes of Doubly``# Linked List in reverse order``def` `reversePrint(head_ref):``    ``tail ``=` `head_ref` `    ``# Traversing till tail of the linked list``    ``while` `(tail.``next` `!``=` `None``):``        ``tail ``=` `tail.``next` `    ``# Traversing linked list from tail``    ``# and pring the node.data``    ``while` `(tail !``=` `head_ref):``        ``print``(tail.data, end ``=` `" "``)``        ``tail ``=` `tail.prev``    ` `    ``print``(tail.data)` `# UTILITY FUNCTIONS``# Function to insert a node at the``# beginging of the Doubly Linked List``def` `push(head_ref, new_data):``    ` `    ``# allocate node``    ``new_node ``=` `Node(new_data)` `    ``# put in the data``    ``new_node.data ``=` `new_data` `    ``# since we are adding at the beginning,``    ``# prev is always None``    ``new_node.prev ``=` `None` `    ``# link the old list off the new node``    ``new_node.``next` `=` `head_ref` `    ``# change prev of head node to new node``    ``if` `(head_ref !``=` `None``):``        ``head_ref.prev ``=` `new_node` `    ``# move the head to po to the new node``    ``head_ref ``=` `new_node``    ``return` `head_ref` `# Driver Code``if` `__name__``=``=``'__main__'``:``    ` `    ``# Start with the empty list``    ``head ``=` `None` `    ``# Let us create a sorted linked list``    ``# to test the functions``    ``# Created linked list will be 10.8.4.2``    ``head ``=` `push(head, ``2``)``    ``head ``=` `push(head, ``4``)``    ``head ``=` `push(head, ``8``)``    ``head ``=` `push(head, ``10``)` `    ``print``(``"Linked List elements in reverse order : "``)` `    ``reversePrint(head)` `# This code is contributed by Srathore`

## C#

 `// C# Program to print doubly``// linked list in reverse order``using` `System;    ``    ` `class` `Sol``{` `// Doubly linked list node``public` `class` `Node``{``    ``public` `int` `data;``    ``public` `Node next;``    ``public` `Node prev;``};` `// Function to print nodes of Doubly``// Linked List in reverse order``static` `void` `reversePrint( Node head_ref)``{``    ``Node tail = head_ref;` `    ``// Traversing till tail of the linked list``    ``while` `(tail.next != ``null``)``    ``{``        ``tail = tail.next;``    ``}` `    ``// Traversing linked list from tail``    ``// and printing the node.data``    ``while` `(tail != head_ref)``    ``{``        ``Console.Write( tail.data + ``" "``);``        ``tail = tail.prev;``    ``}``    ``Console.WriteLine( tail.data );``}` `// UTILITY FUNCTIONS /``// Function to insert a node at the``// beginging of the Doubly Linked List``static` `Node push( Node head_ref, ``int` `new_data)``{``    ``// allocate node``    ``Node new_node = ``new` `Node();` `    ``// put in the data``    ``new_node.data = new_data;` `    ``// since we are adding at the beginning,``    ``// prev is always null``    ``new_node.prev = ``null``;` `    ``// link the old list off the new node``    ``new_node.next = (head_ref);` `    ``// change prev of head node to new node``    ``if` `((head_ref) != ``null``)``        ``(head_ref).prev = new_node;` `    ``// move the head to point to the new node``    ``(head_ref) = new_node;``    ``return` `head_ref;``}` `// Driver Code``public` `static` `void` `Main(String []args)``{``    ``// Start with the empty list``    ``Node head = ``null``;` `    ``// Let us create a sorted linked list``    ``// to test the functions``    ``// Created linked list will be 10.8.4.2``    ``head = push(head, 2);``    ``head = push(head, 4);``    ``head = push(head, 8);``    ``head = push(head, 10);` `    ``Console.Write( ``"Linked List elements in reverse order : "` `);` `    ``reversePrint(head);``}``}` `// This code contributed by Rajput-Ji`

## Javascript

 ``
Output:
```Linked List elements in reverse order :
2 4 8 10```

Attention reader! Don’t stop learning now. Get hold of all the important DSA concepts with the DSA Self Paced Course at a student-friendly price and become industry ready.  To complete your preparation from learning a language to DS Algo and many more,  please refer Complete Interview Preparation Course.

In case you wish to attend live classes with experts, please refer DSA Live Classes for Working Professionals and Competitive Programming Live for Students.

My Personal Notes arrow_drop_up