8086 program to find Square Root of a number

Problem – Write an assembly language program in 8086 microprocessor to find square root of a number.

Example –

Algorithm –

1. Move the input data in register AX
2. Move the data 0000 in CX and FFFF in BX
3. Add 0002 to the contents of BX
4. Increment the content of CX by 1
5. Subtract the contents of AX and BX
6. If Zero Flag(ZF) is not set go to step 3 else go to step 7
7. Store the data from CX to offset 600
8. Stop

Program –

OFFSET	MNEMONICS	COMMENT
0400	MOV AX, [500]	AX <- [500]
0404	MOV CX, 0000	CX <- 0000
0407	MOV BX, FFFF	BX <- FFFF
040A	ADD BX, 02	BX = BX + 02
040E	INC CX	C = C + 1
040F	SUB AX, BX	AX = AX – BX
0411	JNZ 040A	JUMP to 040A if ZF = 0
0413	MOV [600], CX	[600] <- CX
0417	HLT	Stop

Explanation –

1. M0V AX, [500] is used to move the data from offset 500 to register AX
2. MOV CX 0000 is used to move 0000 to register CX
3. MOV BX FFFF is used to move FFFF to register BX
4. ADD BX, 02 is used to add BX and 02
5. INC CX is used to increment the content of CX by 1
6. SUB AX, BX is used to subtract contents of AX with BX
7. JNZ 040A is used to jump to address 040A if zero flag(ZF) is 0
8. MOV [600], CX is used to store the contents of CX to offset 600
9. HLT is used end the program
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