Sum of all the numbers in the Nth row of the given triangle

Given a positive integer N, the task is to find the sum of all the numbers in the Nth row of the below triangle.

1
3 2
6 2 3
10 2 3 4
15 2 3 4 5


Examples:



Input: N = 2
Output: 5
3 + 2 = 5

Input: N = 3
Output: 11
6 + 2 + 3 = 11

Approach: Taking a closer look at the pattern, it can be observed that a series will be formed as 1, 5, 11, 19, 29, 41, 55, … whose Nth term is (N – 1) + N2.

Below is the implementation of the above approach:

C++

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// C++ implementation of the approach
#include <bits/stdc++.h>
using namespace std;
  
// Function to return the sum
// of the nth row elements of
// the given triangle
int getSum(int n)
{
    return ((n - 1) + pow(n, 2));
}
  
// Driver code
int main()
{
    int n = 3;
  
    cout << getSum(n);
  
    return 0;
}

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Java

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// Java implementation of the approach
class GFG
{
      
// Function to return the sum
// of the nth row elements of
// the given triangle
static int getSum(int n)
{
    return ((n - 1) + (int)Math.pow(n, 2));
}
  
// Driver code
public static void main(String[] args)
{
    int n = 3;
  
    System.out.println(getSum(n));
}
}
  
// This code is contributed by Code_Mech

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Python3

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# Python3 implementation of the approach 
  
# Function to return the sum 
# of the nth row elements of 
# the given triangle 
def getSum(n) :
  
    return ((n - 1) + pow(n, 2)); 
  
# Driver code 
if __name__ == "__main__"
  
    n = 3
  
    print(getSum(n)); 
  
# This code is contributed by AnkitRai01

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C#

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// C# implementation of the approach 
using System;
      
class GFG
{
      
// Function to return the sum
// of the nth row elements of
// the given triangle
static int getSum(int n)
{
    return ((n - 1) + (int)Math.Pow(n, 2));
}
  
// Driver code
public static void Main(String[] args)
{
    int n = 3;
  
    Console.WriteLine(getSum(n));
}
}
  
// This code is contributed by 29AjayKumar

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Output:

11


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