Sum of consecutive two elements in a array

Given an array print sum of the pairwise consecutive elements.

Examples:

Input  : 8, 5, 4, 3, 15, 20
Output : 13, 9, 7, 18, 35

Input  : 5, 10, 15, 20
Output : 15, 25, 35



The solution is to traverse the array and saving the sum of consecutive numbers in the variable sum.

C++

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// C++ program to print the 
// sum of the consecutive elements.
#include <stdio.h>
#include <stdlib.h>
  
// Function to print pairwise sum
void pairwiseSum(int arr[], int n) 
{
    int sum = 0;   
    for (int i = 0; i < n - 1; i++) 
    {
        // adding the alternate numbers
        sum = arr[i] + arr[i + 1];
        printf(" %d ", sum);
    }
}
  
// Driver function to test function
int main()
{
    int arr[] = {4, 10, 15, 5, 6};
    int n = sizeof(arr) / sizeof(arr[0]);
      
    pairwiseSum(arr, n);
    return 0;
}

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Java

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// Java program to print the 
// sum of the consecutive elements.
  
class Arraysum {
      
    // Function to print Alternatesum
    static void pairwiseSum(int arr[], int n)
    {
        int sum = 0;
        for (int i = 0; i + 1 < n; i++) 
        {
            // adding the alternate numbers
            sum = arr[i] + arr[i + 1];
            System.out.print(sum + " ");
        }
    }
      
    /*driver function to test function*/
    public static void main(String[] args)
    {
      
        int arr[] = {4, 10, 15, 5, 6};
        int n = arr.length;
        pairwiseSum(arr, n);
    }
}

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Python3

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# Python3 program to print the 
# sum of the consecutive elements.
  
# Function to print alternate sum
def pairwiseSum(lst, n):
    sum = 0;
    for i in range(len(lst)-1):
          
        # adding the alternate numbers
        sum = lst[i] + lst[i + 1]
        print (sum, end = " ")
      
# driver function to test function
arr =[4, 10, 15, 5, 6]
size = len(arr)
pairwiseSum(arr, size)

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C#

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// C# program to print the 
// sum of the consecutive elements.
using System;
  
class Arraysum {
      
    // Function to print Alternatesum
    static void pairwiseSum(int []arr, int n)
    {
        int sum = 0;
        for (int i = 0; i + 1 < n; i++) 
        {
            // adding the alternate numbers
            sum = arr[i] + arr[i + 1];
            Console.Write(sum + " ");
        }
    }
      
    // Driver function 
    public static void Main()
    {
      
        int []arr = {4, 10, 15, 5, 6};
        int n = arr.Length;
        pairwiseSum(arr, n);
    }
}
  
// This code is contributed by vt_m.

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PHP

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<?php
// PHP program to print the 
// sum of the consecutive elements.
  
// Function to print pairwise sum
function pairwiseSum($arr, $n
{
    $sum = 0; 
    for ($i = 0; $i < $n - 1; $i++) 
    {
          
        // adding the alternate numbers
        $sum = $arr[$i] + $arr[$i + 1];
        echo $sum," ";
    }
}
  
    // Driver Code
    $arr = array (4, 10, 15, 5, 6);
    $n = sizeof($arr) ;
    pairwiseSum($arr, $n);
      
// This code is contributed by ajit
?>

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Output:

14 25 20 11


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Improved By : jit_t



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