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Sort a String in decreasing order of values associated after removal of values smaller than X

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Given an integer X and a string str consisting of space-separated texts and numbers placed alternately, the task is to sort the string such that texts and numbers appear in decreasing order of numbers associated after removal of all numbers less than X. If two strings have the same values then sort them in the lexicographic order of the string.

Examples:

Input: X = 79, str = “Geek 78 for 99 Geeks 88 Gfg 86” 
Output:
for 99 Geeks 88 Gfg 86 
Explanation: “Even 99” is removed, since the number associated to it is smaller than X(= 79) Now, the reordered string string based on decreasing order of numbers associated is “Bob 99 Suzy 88 Alice 86”. 

Input: X = 77, str = “Axc 78 Czt 60” 
Output: Axc 78

Approach: The idea is to use the Bubble Sort technique. Follow the steps below to solve the problem:

  • Split the string in to a list, then remove the entries that are less than the given value i.e. X.
  • Sort the list based on the number associated with it using bubble sort method.
  • If the numbers are not equal, sort the numbers in decreasing order and simultaneously sort the names.
  • If the numbers are equal then sort them lexicographically.
  • Swap both the strings and the number together in order to keep them together.

Below is the implementation of the above approach:

C++

// C++ Code
#include <iostream>
#include <vector>
#include <algorithm>
#include <string>
using namespace std;
 
// Function to split the input string into a list
vector<string> tokenizer(string str) {
  vector<string> list;
  string temp = "";
  for (int i = 0; i < str.length(); i++) {
    if (str[i] == ' ') {
      list.push_back(temp);
      temp = "";
    }
    else {
      temp += str[i];
    }
  }
  list.push_back(temp);
  return list;
}
 
// Function to sort the given list based on values at odd indices of the list
string sortListByOddIndices(vector<string> list, int x) {
  int l = list.size();
 
  // Function to remove the values less than the given value x
  for (int i = l - 1; i > 0; i -= 2) {
    if (stoi(list[i]) < x) {
      list.erase(list.begin() + i - 1, list.begin() + i + 1);
    }
  }
 
  l = list.size();
 
  for (int i = 1; i < l; i += 2) {
    for (int j = 1; j < l - i; j += 2) {
      // Compares values at odd indices of the list to sort the list
      if (list[j] < list[j + 2]
          || (list[j - 1] > list[j + 1] && list[j] == list[j + 2])) {
        swap(list[j], list[j + 2]);
        swap(list[j - 1], list[j + 1]);
      }
    }
  }
 
  string sortedList;
  for (int i = 0; i < list.size(); i++) {
    sortedList += list[i];
    sortedList += " ";
  }
 
  return sortedList;
}
 
// Driver code
int main()
{
   
  string str = "Axc 78 Czy 60";
  int x = 77;
 
  // Function call
  vector<string> list = tokenizer(str);
 
  string sortedList = sortListByOddIndices(list, x);
 
  cout << sortedList;
  return 0;
}
 
// This code is contributed by akashish__

                    

Python3

# Python Program to implement
# the above approach
 
# Function to split the input
# string into a list
def tokenizer(Str):
    List = Str.split()
    return List
 
# Function to sort the given list based
# on values at odd indices of the list
def SortListByOddIndices(List, x):
 
    l = len(List)
 
# Function to remove the values
# less than the given value x
    for i in range(l - 1, 0, -2):
        if int(List[i]) < x:
            del(List[i - 1: i + 1])
 
    l = len(List)
 
    for i in range(1, l, 2):
        for j in range(1, l - i, 2):
 
            # Compares values at odd indices of
            # the list to sort the list
            if List[j] < List[j + 2] \
            or (List[j - 1] > List[j + 1] \
            and List[j] == List[j + 2]):
                 
                List[j], List[j + 2] \
                = List[j + 2], List[j]
                 
                List[j - 1], List[j + 1] \
                = List[j + 1], List[j - 1]
 
    return ' '.join(List)
 
 
# Driver Code
Str = "Axc 78 Czy 60"
x = 77
 
# Function call
List = tokenizer(Str)
 
Str = SortListByOddIndices(List, x)
 
print(Str)

                    

Javascript

// Function to split the input string into a list
function tokenizer(str) {
  const list = str.split(' ');
  return list;
}
 
// Function to sort the given list based on values at odd indices of the list
function sortListByOddIndices(list, x) {
  var l = list.length;
 
  // Function to remove the values less than the given value x
  for (let i = l - 1; i > 0; i -= 2) {
    if (Number(list[i]) < x) {
      list.splice(i - 1, 2);
    }
  }
 
  l = list.length;
 
  for (let i = 1; i < l; i += 2) {
    for (let j = 1; j < l - i; j += 2) {
      // Compares values at odd indices of the list to sort the list
      if (list[j] < list[j + 2]
        || (list[j - 1] > list[j + 1] && list[j] === list[j + 2])) {
        [list[j], list[j + 2]] = [list[j + 2], list[j]];
        [list[j - 1], list[j + 1]] = [list[j + 1], list[j - 1]];
      }
    }
  }
 
  return list.join(' ');
}
 
// Driver code
const str = 'Axc 78 Czy 60';
const x = 77;
 
// Function call
const list = tokenizer(str);
 
const sortedList = sortListByOddIndices(list, x);
 
console.log(sortedList);

                    

C#

// C# Code
using System;
using System.Collections.Generic;
using System.Linq;
 
public class GFG{
    // Function to split the input string into a list
    static List<string> Tokenizer(string str)
    {
        List<string> list = new List<string>();
        string temp = "";
        for (int i = 0; i < str.Length; i++) {
            if (str[i] == ' ') {
                list.Add(temp);
                temp = "";
            }
            else {
                temp += str[i];
            }
        }
        list.Add(temp);
        return list;
    }
 
    // Function to sort the given list based on values at
    // odd indices of the list
    static string SortListByOddIndices(List<string> list,
                                       int x)
    {
        int l = list.Count;
 
        // Function to remove the values less than the given
        // value x
        for (int i = l - 1; i > 0; i -= 2) {
            if (Int32.Parse(list[i]) < x) {
                list.RemoveRange(i - 1, 2);
            }
        }
 
        l = list.Count;
 
        for (int i = 1; i < l; i += 2) {
            for (int j = 1; j < l - i; j += 2) {
                // Compares values at odd indices of the
                // list to sort the list
                if (list[j] == list[j + 2]) {
                    if (list[j - 1].Length > list[j + 1].Length) {
                        string temp1 = list[j];
                        string temp2 = list[j - 1];
                        list[j] = list[j + 2];
                        list[j - 1] = list[j + 1];
                        list[j + 2] = temp1;
                        list[j + 1] = temp2;
                    }
                }
                else if (list[j].Length < list[j + 2].Length) {
                    string temp1 = list[j];
                    string temp2 = list[j - 1];
                    list[j] = list[j + 2];
                    list[j - 1] = list[j + 1];
                    list[j + 2] = temp1;
                    list[j + 1] = temp2;
                }
            }
        }
 
        string sortedList = string.Join(" ", list);
 
        return sortedList;
    }
 
    // Driver code
 
    static public void Main (){
        string str = "Axc 78 Czy 60";
        int x = 77;
 
        // Function call
        List<string> list = Tokenizer(str);
 
        string sortedList = SortListByOddIndices(list, x);
 
        Console.WriteLine(sortedList);
        Console.ReadLine();
    }
}
// contributed by akashish__

                    

Java

// Java code for the above approach
 
import java.util.ArrayList;
import java.util.List;
 
public class Main {
 
    // Function to split the input
    // string into a list
    public static List<String> tokenizer(String Str) {
        List<String> List = new ArrayList<>();
        for (String s : Str.split("\\s+")) {
            List.add(s);
        }
        return List;
    }
 
    // Function to sort the given list based
    // on values at odd indices of the list
    public static String SortListByOddIndices(List<String> List, int x) {
 
        int l = List.size();
 
        // Function to remove the values
        // less than the given value x
        for (int i = l - 1; i >= 0; i -= 2) {
            if (Integer.parseInt(List.get(i)) < x) {
                List.remove(i - 1);
                List.remove(i - 1);
            }
        }
 
        l = List.size();
 
        for (int i = 1; i < l; i += 2) {
            for (int j = 1; j < l - i; j += 2) {
 
                // Compares values at odd indices of
                // the list to sort the list
                if (List.get(j).compareTo(List.get(j + 2)) < 0
                        || (List.get(j - 1).compareTo(List.get(j + 1)) > 0
                        && List.get(j).equals(List.get(j + 2)))) {
 
                    String temp1 = List.get(j);
                    String temp2 = List.get(j - 1);
 
                    List.set(j, List.get(j + 2));
                    List.set(j + 2, temp1);
 
                    List.set(j - 1, List.get(j + 1));
                    List.set(j + 1, temp2);
                }
            }
        }
 
        return String.join(" ", List);
    }
 
    // Driver Code
    public static void main(String[] args) {
 
        String Str = "Axc 78 Czy 60";
        int x = 77;
 
        // Function call
        List<String> List = tokenizer(Str);
 
        Str = SortListByOddIndices(List, x);
 
        System.out.println(Str);
    }
}
 
// This code is contributed by princekumaras

                    
Output:
Axc 78

Time Complexity: O(N2
Auxiliary Space: O(N)



Last Updated : 16 Mar, 2023
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