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Smallest N digit number which is a perfect fourth power
• Last Updated : 01 Apr, 2021

Given an integer N, the task is to find the smallest N-digit number which is a perfect fourth power.
Examples:

Input: N = 2
Output: 16
Only valid numbers are 24 = 16
and 34 = 81 but 16 is the minimum.
Input: N = 3
Output: 256
44 = 256

Approach: It can be observed that for the values of N = 1, 2, 3, …, the series will go on like 1, 16, 256, 1296, 10000, 104976, 1048576, … whose Nth term will be pow(ceil( (pow(pow(10, (n – 1)), 1 / 4) ) ), 4).
Below is the implementation of the above approach:

## C++

 `// C++ implementation of the approach``#include ` `using` `namespace` `std;` `// Function to return the smallest n-digit``// number which is a perfect fourth power``int` `cal(``int` `n)``{``    ``double` `res = ``pow``(``ceil``((``pow``(``pow``(10,``                          ``(n - 1)), 1 / 4) )), 4);``    ``return` `(``int``)res;``}` `// Driver code``int` `main()``{``    ``int` `n = 1;``    ``cout << (cal(n));``}` `// This code is contributed by Mohit Kumar`

## Java

 `// Java implementation of the approach``class` `GFG``{` `// Function to return the smallest n-digit``// number which is a perfect fourth power``static` `int` `cal(``int` `n)``{``    ``double` `res = Math.pow(Math.ceil((``                 ``Math.pow(Math.pow(``10``,``                ``(n - ``1``)), ``1` `/ ``4``) )), ``4``);``    ``return` `(``int``)res;``}` `// Driver code``public` `static` `void` `main(String[] args)``{``    ``int` `n = ``1``;``    ``System.out.println(cal(n));``}``}` `// This code is contributed by CodeMech`

## Python3

 `# Python3 implementation of the approach``from` `math ``import` `*` `# Function to return the smallest n-digit``# number which is a perfect fourth power``def` `cal(n):``    ``res ``=` `pow``(ceil( (``pow``(``pow``(``10``, (n ``-` `1``)), ``1` `/` `4``) ) ), ``4``)``    ``return` `int``(res)` `# Driver code``n ``=` `1``print``(cal(n))`

## C#

 `// C# implementation of the approach``using` `System;` `class` `GFG``{` `// Function to return the smallest n-digit``// number which is a perfect fourth power``static` `int` `cal(``int` `n)``{``    ``double` `res = Math.Pow(Math.Ceiling((``                 ``Math.Pow(Math.Pow(10,``                 ``(n - 1)), 1 / 4) )), 4);``    ``return` `(``int``)res;``}` `// Driver code``public` `static` `void` `Main()``{``    ``int` `n = 1;``    ``Console.Write(cal(n));``}``}` `// This code is contributed``// by Akanksha_Rai`

## Javascript

 ``
Output:
`1`

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