Python | Update each element in tuple list

Sometimes, while working with data, we can have a problem in which we need to perform update operations on tuples. This can have applications across many domains such as web development. Let’s discuss certain ways in which this task can be performed.

Method #1 : Using list comprehension
This is shorthand to brute function that can be applied to perform this task. In this, we iterate for each element of each tuple to perform bulk update of data.

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# Python3 code to demonstrate working of
# Update each element in tuple list
# Using list comprehension
  
# initialize list
test_list = [(1, 3, 4), (2, 4, 6), (3, 8, 1)]
  
# printing original list 
print("The original list : " + str(test_list))
  
# initialize add element
add_ele = 4
  
# Update each element in tuple list
# Using list comprehension
res = [tuple(j + add_ele for j in sub ) for sub in test_list]
  
# printing result
print("List after bulk update : " + str(res))

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Output :

The original list : [(1, 3, 4), (2, 4, 6), (3, 8, 1)]
List after bulk update : [(5, 7, 8), (6, 8, 10), (7, 12, 5)]

 

Method #2 : Using map() + lambda + list comprehension
The combination of above functions can be used to perform this task. In this, we just iterate for all elements using map() and extend logic of update using lambda function.



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code

# Python3 code to demonstrate working of
# Update each element in tuple list
# Using list comprehension + map() + lambda
  
# initialize list
test_list = [(1, 3, 4), (2, 4, 6), (3, 8, 1)]
  
# printing original list 
print("The original list : " + str(test_list))
  
# initialize add element
add_ele = 4
  
# Update each element in tuple list
# Using list comprehension + map() + lambda
res = [tuple(map(lambda ele : ele + add_ele, sub)) for sub in test_list]
  
# printing result
print("List after bulk update : " + str(res))

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Output :

The original list : [(1, 3, 4), (2, 4, 6), (3, 8, 1)]
List after bulk update : [(5, 7, 8), (6, 8, 10), (7, 12, 5)]

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