Python | Replace tuple according to Nth tuple element
Sometimes, while working with data, we might have a problem in which we need to replace the entry in which a particular entry of data is matching. This can be a matching phone no, id etc. This has it’s application in web development domain. Let’s discuss certain ways in which this task can be performed.
Method #1 : Using loop + enumerate()
This task can be performed using the combination of loops and enumerate function which can help to access to the Nth element and then check and replace when the condition is satisfied.
# Python3 code to demonstrate working of # Replace tuple according to Nth tuple element # Using loops + enumerate() # Initializing list test_list = [('gfg', 1), ('was', 2), ('best', 3)] # printing original list print("The original list is : " + str(test_list)) # Initializing change record repl_rec = ('is', 2) # Initializing N N = 1 # Replace tuple according to Nth tuple element # Using loops + enumerate() for key, val in enumerate(test_list): if val[N] == repl_rec[N]: test_list[key] = repl_rec break # printing result print("The tuple after replacement is : " + str(test_list)) |
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Output :
The original list is : [('gfg', 1), ('was', 2), ('best', 3)]
The tuple after replacement is : [('gfg', 1), ('is', 2), ('best', 3)]
Method #2 : Using list comprehension
This is the one-liner approach to solve this particular problem. In this, we just iterate the list element and keep matching the matching Nth element of tuple and perform replacement.
# Python3 code to demonstrate working of # Replace tuple according to Nth tuple element # Using list comprehension # Initializing list test_list = [('gfg', 1), ('was', 2), ('best', 3)] # printing original list print("The original list is : " + str(test_list)) # Initializing change record repl_rec = ('is', 2) # Initializing N N = 1 # Replace tuple according to Nth tuple element # Using list comprehension res = [repl_rec if sub[N] == repl_rec[N] else sub for sub in test_list] # printing result print("The tuple after replacement is : " + str(res)) |
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Output :
The original list is : [('gfg', 1), ('was', 2), ('best', 3)]
The tuple after replacement is : [('gfg', 1), ('is', 2), ('best', 3)]
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