# Python | Select dictionary with condition given key greater than k

In Python, sometimes we require to get only some of the dictionary required to solve the problem. This problem is quite common in web development that we require to get only the selective dictionary satisfying some given criteria. Let’s discuss certain ways in which this problem can be solved.

Method #1: Using list comprehension

 `# Python3 code to demonstrate ` `# filtering of a list of dictionary ` `# on basis of condition ` ` `  `# initialising list of dictionary ` `ini_list ``=` `[{``'a'``:``1``, ``'b'``:``3``, ``'c'``:``7``}, {``'a'``:``3``, ``'b'``:``8``, ``'c'``:``17``}, ` `            ``{``'a'``:``78``, ``'b'``:``12``, ``'c'``:``13``}, {``'a'``:``2``, ``'b'``:``2``, ``'c'``:``2``}] ` ` `  `# printing initial list of dictionary ` `print` `(``"initial_list"``, ``str``(ini_list)) ` ` `  `# code to filter list ` `# where c is greater than 10 ` `res ``=` `[d ``for` `d ``in` `ini_list ``if` `d[``'c'``] > ``10``] ` ` `  `# printing result ` `print` `(``"resultant_list"``, ``str``(res)) `

Output:

initial_list [{‘c’: 7, ‘b’: 3, ‘a’: 1}, {‘c’: 17, ‘b’: 8, ‘a’: 3}, {‘c’: 13, ‘b’: 12, ‘a’: 78}, {‘c’: 2, ‘b’: 2, ‘a’: 2}]
resultant_list [{‘c’: 17, ‘b’: 8, ‘a’: 3}, {‘c’: 13, ‘b’: 12, ‘a’: 78}]

Method #2: Using lambda and filter

 `# Python3 code to demonstrate ` `# filtering of list of dictionary ` `# on basis of condition ` ` `  `# initialising list of dictionary ` `ini_list ``=` `[{``'a'``:``1``, ``'b'``:``3``, ``'c'``:``7``}, {``'a'``:``3``, ``'b'``:``8``, ``'c'``:``17``}, ` `            ``{``'a'``:``78``, ``'b'``:``12``, ``'c'``:``13``}, {``'a'``:``2``, ``'b'``:``2``, ``'c'``:``2``}] ` ` `  `# printing initial list of dictionary ` `print` `(``"initial_list"``, ``str``(ini_list)) ` ` `  `# code to filter list ` `# where c is less than 10 ` `res ``=` `list``(``filter``(``lambda` `x:x[``"c"``] > ``10``, ini_list )) ` ` `  `# printing result ` `print` `(``"resultant_list"``, ``str``(res)) `

Output:

initial_list [{‘b’: 3, ‘c’: 7, ‘a’: 1}, {‘b’: 8, ‘c’: 17, ‘a’: 3}, {‘b’: 12, ‘c’: 13, ‘a’: 78}, {‘b’: 2, ‘c’: 2, ‘a’: 2}]
resultant_list [{‘c’: 17, ‘b’: 8, ‘a’: 3}, {‘c’: 13, ‘b’: 12, ‘a’: 78}]

Method #3: Using dict comprehension and list comprehension

 `# Python3 code to demonstrate ` `# filtering of list of dictionary ` `# on basis of condition ` ` `  `# initialising list of dictionary ` `ini_list ``=` `[{``'a'``:``1``, ``'b'``:``3``, ``'c'``:``7``}, {``'a'``:``3``, ``'b'``:``8``, ``'c'``:``17``}, ` `            ``{``'a'``:``78``, ``'b'``:``12``, ``'c'``:``13``}, {``'a'``:``2``, ``'b'``:``2``, ``'c'``:``10``}] ` `                 `  `# printing initial list of dictionary ` `print` `(``"initial_list"``, ``str``(ini_list)) ` ` `  `# code to filter list ` `# where c is more than 10 ` ` `  `res ``=` `[{ k:v ``for` `(k, v) ``in` `i.items()}  ` `        ``for` `i ``in` `ini_list ``if` `i.get(``'c'``) > ``10``] ` ` `  `# printing result ` `print` `(``"resultant_list"``, ``str``(res)) `

Output:

initial_list [{‘a’: 1, ‘c’: 7, ‘b’: 3}, {‘a’: 3, ‘c’: 17, ‘b’: 8}, {‘a’: 78, ‘c’: 13, ‘b’: 12}, {‘a’: 2, ‘c’: 10, ‘b’: 2}]
resultant_list [{‘a’: 3, ‘c’: 17, ‘b’: 8}, {‘a’: 78, ‘c’: 13, ‘b’: 12}]

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