# Python | Records with Key’s value greater than K

The problem of getting the suitable dictionaries that has a atleast value of the corresponding key is quite common when one starts working with dictionary. Let’s discuss certain ways in which this task can be performed.

Method #1 : Using loop
This is the brute force method by which this task can be performed. For this, we just use naive check and compare and append the records which have a particular key’s value greater than K.

 `# Python3 code to demonstrate working of ` `# Records with Key's value greater than K ` `# Using loop ` ` `  `# Initialize list ` `test_list ``=` `[{``'gfg'` `: ``2``, ``'is'` `: ``4``, ``'best'` `: ``6``},  ` `            ``{``'it'` `: ``5``, ``'is'` `: ``7``, ``'best'` `: ``8``}, ` `            ``{``'CS'` `: ``10``, ``'is'` `: ``8``, ``'best'` `: ``10``}] ` ` `  `# Printing original list ` `print``(``"The original list is : "` `+` `str``(test_list)) ` ` `  `# Initialize K  ` `K ``=` `6` ` `  `# Using loop ` `# Records with Key's value greater than K ` `res ``=` `[] ` `for` `sub ``in` `test_list: ` `    ``if` `sub[``'is'``] >``=` `K: ` `        ``res.append(sub) ` ` `  `# printing result  ` `print``(``"The filtered dictionary records is : "` `+` `str``(res)) `

Output :

```The original list is : [{'best': 6, 'gfg': 2, 'is': 4}, {'best': 8, 'it': 5, 'is': 7}, {'best': 10, 'CS': 10, 'is': 8}]
The filtered dictionary records is : [{'best': 8, 'it': 5, 'is': 7}, {'best': 10, 'CS': 10, 'is': 8}]
```

Method #2 : Using `list()` + dictionary comprehension
The combination of these methods can also be used to perform this task. This difference is that it’s a one liner and more efficient as list function uses iterator as internal implementation which are quicker than generic methods.

 `# Python3 code to demonstrate working of ` `# Find dictionary matching value in list ` `# Using list() + dictionary comprehension ` ` `  `# Initialize list ` `test_list ``=` `[{``'gfg'` `: ``2``, ``'is'` `: ``4``, ``'best'` `: ``6``},  ` `            ``{``'it'` `: ``5``, ``'is'` `: ``7``, ``'best'` `: ``8``}, ` `            ``{``'CS'` `: ``10``, ``'is'` `: ``8``, ``'best'` `: ``10``}] ` ` `  `# Printing original list ` `print``(``"The original list is : "` `+` `str``(test_list)) ` ` `  `# Initialize K  ` `K ``=` `6` ` `  `# Using list() + dictionary comprehension ` `# Find dictionary matching value in list ` `res ``=` `list``((sub ``for` `sub ``in` `test_list ``if` `sub[``'is'``] >``=` `K)) ` ` `  `# printing result  ` `print``(``"The filtered dictionary records : "` `+` `str``(res)) `

Output :

```The original list is : [{'best': 6, 'gfg': 2, 'is': 4}, {'best': 8, 'it': 5, 'is': 7}, {'best': 10, 'CS': 10, 'is': 8}]
The filtered dictionary records is : [{'best': 8, 'it': 5, 'is': 7}, {'best': 10, 'CS': 10, 'is': 8}]
```

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