Sometimes, while working with Python tuples, we can have a problem in which we need to remove duplicates on basis of equal length and equal sum. This kind of problem can also be broken to accomodate any one of the required condition. This kind of problem can occur in data domains and day-day programming. Let’s discuss certain ways in which this task can be performed.
Input : test_list = [(1, 2, 0), (3, 0), (2, 1)]
Output : [(1, 2, 0), (3, 0)]Input : test_list = [(1, 2, 0), (3, 0, 0), (0, 2, 1)]
Output : [(1, 2, 0)]
Method #1 : Using nested loops
This is one of the ways in which this task can be performed. This is brute force method, in which we loop for each tuple, a matching tuple w.r.t size and sum and perform removal.
# Python3 code to demonstrate working of # Remove Equilength and Equisum Tuple Duplicates # Using nested loop # initializing lists test_list = [( 4 , 5 , 6 ), ( 3 , 0 ), ( 2 , 1 ), ( 1 , 2 , 3 ), ( 5 , 5 , 5 )] # printing original list print ( "The original list is : " + str (test_list)) # Remove Equilength and Equisum Tuple Duplicates # Using nested loop res = [] for sub in test_list: for sub1 in res: if len (sub) = = len (sub1) and sum (sub) = = sum (sub1): break else : res.append(sub) # printing result print ( "Tuples after filteration : " + str (res)) |
The original list is : [(4, 5, 6), (3, 0), (2, 1), (1, 2, 3), (5, 5, 5)] Tuples after filteration : [(4, 5, 6), (3, 0), (1, 2, 3)]
Method #2 : Using dict() + values()
The combination of above functions offer another way to solve this problem. In this, we just harness the property of dictionary of having unique keys and create a tuple key with len and sum of tuples. The duplicates are thus, avoided.
# Python3 code to demonstrate working of # Remove Equilength and Equisum Tuple Duplicates # Using dict() + values() # initializing lists test_list = [( 4 , 5 , 6 ), ( 3 , 0 ), ( 2 , 1 ), ( 1 , 2 , 3 ), ( 5 , 5 , 5 )] # printing original list print ( "The original list is : " + str (test_list)) # Remove Equilength and Equisum Tuple Duplicates # Using dict() + values() res = list ({( len (sub), sum (sub)): sub for sub in test_list}.values()) # printing result print ( "Tuples after filteration : " + str (res)) |
The original list is : [(4, 5, 6), (3, 0), (2, 1), (1, 2, 3), (5, 5, 5)] Tuples after filteration : [(4, 5, 6), (3, 0), (1, 2, 3)]
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