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Python program to Sort a List of Dictionaries by the Sum of their Values

  • Last Updated : 24 Oct, 2020

Given Dictionary List, sort by summation of their values. 

Input : test_list = [{1 : 3, 4 : 5, 3 : 5}, {1 : 100}, {8 : 9, 7 : 3}] 
Output : [{8: 9, 7: 3}, {1: 3, 4: 5, 3: 5}, {1: 100}] 
Explanation : 12 < 13 < 100, sorted by values sum.

Input : test_list = [{1 : 100}, {8 : 9, 7 : 3}] 
Output : [{8: 9, 7: 3}, {1: 100}] 
Explanation : 12 < 100, sorted by values sum. 

Method #1 : Using sort() + sum() + values()

In this, the task of performing sort is done using sort(), and sum() and values() are used to get a summation of all the values of the dictionary.

Python3




# Python3 code to demonstrate working of 
# Sort Dictionaries by Values Sum
# Using sort() + sum() + values()
  
def values_sum(row):
      
    # return values sum 
    return sum(list(row.values()))
  
# initializing list
test_list = [{1 : 3, 4 : 5, 3 : 5}, {1 : 7, 10 : 1, 3 : 10}, {1 : 100}, {8 : 9, 7 : 3}]
  
# printing original list
print("The original list is : " + str(test_list))
  
# performing sort  
test_list.sort(key = values_sum)
  
# printing result 
print("Sorted Dictionaries List : " + str(test_list))

Output:

The original list is : [{1: 3, 4: 5, 3: 5}, {1: 7, 10: 1, 3: 10}, {1: 100}, {8: 9, 7: 3}]
Sorted Dictionaries List : [{8: 9, 7: 3}, {1: 3, 4: 5, 3: 5}, {1: 7, 10: 1, 3: 10}, {1: 100}]

Method #2 : Using sorted() + lambda + sum() + values()

In this, we perform sort using sorted() and provide logic using lambda function. 

Python3




# Python3 code to demonstrate working of 
# Sort Dictionaries by Values Sum
# Using sorted() + lambda + sum() + values()
  
# initializing list
test_list = [{1 : 3, 4 : 5, 3 : 5}, {1 : 7, 10 : 1, 3 : 10}, {1 : 100}, {8 : 9, 7 : 3}]
  
# printing original list
print("The original list is : " + str(test_list))
  
# lambda function to get values sum 
res = sorted(test_list, key = lambda row : sum(list(row.values())))
  
# printing result 
print("Sorted Dictionaries List : " + str(res))

Output:

The original list is : [{1: 3, 4: 5, 3: 5}, {1: 7, 10: 1, 3: 10}, {1: 100}, {8: 9, 7: 3}]
Sorted Dictionaries List : [{8: 9, 7: 3}, {1: 3, 4: 5, 3: 5}, {1: 7, 10: 1, 3: 10}, {1: 100}]


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