Python program to remove rows with duplicate element in Matrix
Given Matrix, remove all rows which have duplicate elements in them.
Input : test_list = [[4, 3, 2], [7, 6, 7], [2, 4, 4], [8, 9, 9]]
Output : [[4, 3, 2]]
Explanation : [4, 3, 2] is the only unique row.Input : test_list = [[4, 3, 3, 2], [7, 6, 7], [2, 4, 4], [8, 9, 9]]
Output : []
Explanation : No unique row.
Method 1 : Using list comprehension + set() + len()
In this, we extract only the rows which remain in the same length after converting it into a set.
Python3
# initializing listtest_list = [[4, 3, 2], [7, 6, 7], [2, 4, 5], [8, 9, 9]] # printing original listprint("The original list is : " + str(test_list)) # set() removing all elements# list comprehension used to filterres = [sub for sub in test_list if len(set(sub)) == len(sub)] # printing resultprint("Rows after removal : " + str(res)) |
Output
The original list is : [[4, 3, 2], [7, 6, 7], [2, 4, 5], [8, 9, 9]] Rows after removal : [[4, 3, 2], [2, 4, 5]]
Method #2 : Using filter() + lambda + set() + len()
In this, we perform the task of filtering using filter() + lambda function, and set and len() are used to check.
Python3
# initializing listtest_list = [[4, 3, 2], [7, 6, 7], [2, 4, 5], [8, 9, 9]] # printing original listprint("The original list is : " + str(test_list)) # set() removing all elements# filter() used to filterres = list(filter(lambda ele: len(set(ele)) == len(ele), test_list)) # printing resultprint("Rows after removal : " + str(res)) |
Output
The original list is : [[4, 3, 2], [7, 6, 7], [2, 4, 5], [8, 9, 9]] Rows after removal : [[4, 3, 2], [2, 4, 5]]
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