Python program to find uncommon words from two Strings

Given two sentences as strings A and B. The task is to return a list of all uncommon words. A word is uncommon if it appears exactly once in any one of the sentences, and does not appear in the other sentence.

Note: A sentence is a string of space-separated words. Each word consists only of lowercase letters.

Examples:

Input : A = "Geeks for Geeks" 
        B = "Learning from Geeks for Geeks"
Output : ['Learning', 'from']

Input : A = "apple banana mango" 
        B = "banana fruits mango"
Output : ['apple', 'fruits']

Approach: Every uncommon word occurs exactly once in any one of the strings. So, we make a hash to count the number of occurrences of every word, then return a list of words that occurs exactly once.

Below is the implementation of the above approach:



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# Python3 program to find a list of uncommon words
  
# Function to return all uncommon words
def UncommonWords(A, B):
  
    # count will contain all the word counts
    count = {}
      
    # insert words of string A to hash
    for word in A.split():
        count[word] = count.get(word, 0) + 1
      
    # insert words of string B to hash
    for word in B.split():
        count[word] = count.get(word, 0) + 1
  
    # return required list of words
    return [word for word in count if count[word] == 1]
  
# Driver Code
A = "Geeks for Geeks"
B = "Learning from Geeks for Geeks"
  
# Print required answer
print(UncommonWords(A, B))

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Output:


['from', 'Learning']







Another way to solve this problem:











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def uncommon(a,b): 


    list_a = a.split() 


    list_b = b.split() 


    uc = '' 


    for i in list_a: 


        if i not in list_b: 


            uc = uc+" "+i 


    for j in list_b: 


        if j not in list_a: 


            uc = uc+" "+j 


  


    return uc 


  


# Driver code 


a = "apple banana mango"


b = "banana fruits mango"


print(uncommon(a,b)) 



















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Output:


['apple','fruits']





Also another way-using in-built function “symmetric_difference()”











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def uncommon(a,b): 


  a=a.split() 


  b=b.split() 


  k=set(a).symmetric_difference(set(b)) 


  return k 


  


#Driver code 


if __name__=="__main__": 


  a="apple banana mango" 


  b="banana fruits mango"


  print(list(uncommon(a,b))) 



















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Output:


['apple', 'fruits']





 Another way to solve this problem











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def uncommon(A, B): 


    un_comm = [i for i in "".join(B).split() if i not in "".join(A).split()] 


    return un_comm 


  


#Driver code 


A = "Geeks for Geeks" 


B = "Learning from Geeks for Geeks"


print(uncommon(A, B)) 



















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Output:


['Learning', 'from']







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