Python Program to Print uncommon elements from two sorted arrays
Given two sorted arrays of distinct elements, we need to print those elements from both arrays that are not common. The output should be printed in sorted order.
Examples :
Input : arr1[] = {10, 20, 30}
arr2[] = {20, 25, 30, 40, 50}
Output : 10 25 40 50
We do not print 20 and 30 as these
elements are present in both arrays.
Input : arr1[] = {10, 20, 30}
arr2[] = {40, 50}
Output : 10 20 30 40 50
Method 1:
The idea is based on the merge process of merge sort. We traverse both arrays and skip common elements.
Python3
def printUncommon(arr1, arr2, n1, n2):
i = 0
j = 0
k = 0
while (i < n1 and j < n2):
if (arr1[i] < arr2[j]):
print (arr1[i], end = " " )
i = i + 1
k = k + 1
elif (arr2[j] < arr1[i]):
print (arr2[j], end = " " )
k = k + 1
j = j + 1
else :
i = i + 1
j = j + 1
while (i < n1):
print (arr1[i], end = " " )
i = i + 1
k = k + 1
while (j < n2):
print (arr2[j], end = " " )
j = j + 1
k = k + 1
arr1 = [ 10 , 20 , 30 ]
arr2 = [ 20 , 25 , 30 , 40 , 50 ]
n1 = len (arr1)
n2 = len (arr2)
printUncommon(arr1, arr2, n1, n2)
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Time Complexity: O(n1 + n2), where n1 and n2 represents the size of the given two arrays.
Auxiliary Space: O(1), no extra space is required, so it is a constant.
Method 2: Using Counter() function
Python3
from collections import Counter
def printUncommon(arr1, arr2):
frequency_arr1 = Counter(arr1)
frequency_arr2 = Counter(arr2)
result = []
for key in frequency_arr1:
if key not in frequency_arr2:
result.append(key)
for key in frequency_arr2:
if key not in frequency_arr1:
result.append(key)
result.sort()
for i in result:
print (i, end = ' ' )
arr1 = [ 10 , 20 , 30 ]
arr2 = [ 20 , 25 , 30 , 40 , 50 ]
printUncommon(arr1, arr2)
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Please refer complete article on Print uncommon elements from two sorted arrays for more details!
Time Complexity: O(n*logn), as sort() function is used.
Auxiliary Space : O(n), where n is length of result list.
Method 3: using operator.countOf() method
Python3
import operator as op
def printUncommon(arr1, arr2):
result = []
for key in arr1:
if op.countOf(arr2, key) = = 0 :
result.append(key)
for key in arr2:
if op.countOf(arr1, key) = = 0 :
result.append(key)
result.sort()
for i in result:
print (i, end = ' ' )
arr1 = [ 10 , 20 , 30 ]
arr2 = [ 20 , 25 , 30 , 40 , 50 ]
printUncommon(arr1, arr2)
|
Time Complexity: O(NLogN)
Auxiliary Space : O(N)
Last Updated :
18 Apr, 2023
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