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Python program to check whether the values of a dictionary are in same order as in a list

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  • Last Updated : 11 Oct, 2020

Given a dictionary, test if values are in order with list values.

Input : test_dict = {“gfg” : 4, “is” : 10, “best” : 11}, sub_list = [4, 10, 11] 
Output : True 
Explanation : Values are 4, 10, 11, same as list order. Hence True is returned.
 

Input : test_dict = {“gfg” : 4, “is” : 10, “best” : 11}, sub_list = [4, 11, 10] 
Output : False 
Explanation : Values are 4, 10, 11, list order is 4, 11, 10, not same order. Hence False is returned. 

Method #1 : Using loop

In this, we iterate for dictionary values and list alongside, and test if all the values are in order, flag off in case any element is out of order.

Python3




# Python3 code to demonstrate working of 
# Test for Ordered values from List
# Using loop
  
# initializing dictionary
test_dict = {"gfg" : 4, "is" : 10, "best" : 11, "for" : 19, "geeks" : 1}
  
# printing original dictionary
print("The original dictionary is : " + str(test_dict))
  
# initializing list 
sub_list = [4, 10, 11, 19, 1]
  
idx = 0
res = True
for key in test_dict:
      
    # checking for inequality in order
    if test_dict[key] != sub_list[idx]:
        res = False
        break
    idx += 1
      
# printing result 
print("Are values in order : " + str(res)) 

Output:

The original dictionary is : {‘gfg’: 4, ‘is’: 10, ‘best’: 11, ‘for’: 19, ‘geeks’: 1}
Are values in order : True

Method #2 : Using values() + comparison operators

In this, we extract all the values using values() and then use comparison operators to check for equality with list.

Python3




# Python3 code to demonstrate working of 
# Test for Ordered values from List
# Using values() + comparison operators
  
# initializing dictionary
test_dict = {"gfg" : 4, "is" : 10, "best" : 11, "for" : 19, "geeks" : 1}
  
# printing original dictionary
print("The original dictionary is : " + str(test_dict))
  
# initializing list 
sub_list = [4, 10, 11, 19, 1]
  
# comparing values with list
res = list(test_dict.values()) == sub_list
      
# printing result 
print("Are values in order : " + str(res)) 

Output:

The original dictionary is : {‘gfg’: 4, ‘is’: 10, ‘best’: 11, ‘for’: 19, ‘geeks’: 1}
Are values in order : True


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