Given a positive integer N, count all possible distinct binary strings of length N such that there are no consecutive 1’s.
Examples:
Input: N = 2 Output: 3 // The 3 strings are 00, 01, 10 Input: N = 3 Output: 5 // The 5 strings are 000, 001, 010, 100, 101
Recommended: Please solve it on “PRACTICE ” first, before moving on to the solution.
Python3
# Python program to count # all distinct binary strings # without two consecutive 1's def countStrings(n): a =[0 for i in range(n)] b =[0 for i in range(n)] a[0] = b[0] = 1 for i in range(1, n): a[i] = a[i-1] + b[i-1] b[i] = a[i-1] return a[n-1] + b[n-1] # Driver program to test # above functions print(countStrings(3)) # This code is contributed # by Anant Agarwal. |
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Output:
5
Please refer complete article on Count number of binary strings without consecutive 1’s for more details!
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