Python | Convert a list to dictionary
Given a list, write a Python program to convert the given list to dictionary such that all the odd elements have the key, and even number elements have the value. Since python dictionary is unordered, the output can be in any order.
Examples:
Input : ['a', 1, 'b', 2, 'c', 3]
Output : {'a': 1, 'b': 2, 'c': 3}
Input : ['Delhi', 71, 'Mumbai', 42]
Output : {'Delhi': 71, 'Mumbai': 42}
Method #1 : dict comprehension
To convert a list to dictionary, we can use list comprehension and make a key:value pair of consecutive elements. Finally, typecase the list to dict type.
Python3
# Python3 program to Convert a# list to dictionarydef Convert(lst): res_dct = {lst[i]: lst[i + 1] for i in range(0, len(lst), 2)} return res_dct # Driver codelst = ['a', 1, 'b', 2, 'c', 3]print(Convert(lst)) |
Output
{'a': 1, 'b': 2, 'c': 3}
Method #2 : Using zip() method
First create an iterator, and initialize it to variable ‘it’. Then use zip method, to zip keys and values together. Finally typecast it to dict type.
Python3
# Python3 program to Convert a# list to dictionarydef Convert(a): it = iter(a) res_dct = dict(zip(it, it)) return res_dct # Driver codelst = ['a', 1, 'b', 2, 'c', 3]print(Convert(lst)) |
Output
{'a': 1, 'b': 2, 'c': 3}
