Python | Percentage increase in the total surface area of the cuboid
Given a cuboid of length L, breadth B and Height H, the task is to find percentage increase in the total surface area of the cuboid if length, breadth and height are increased by fixed percentages.
Examples:
Input : L = 20, B = 30, H = 50, l = 10 %, b = 12 %, h = 15 % Output : 26.97 % Input : L = 40, B = 60, H = 15, l = 5 %, b = 7 %, h = 12 % Output : 14.88 %
Code : Python code to find the increase in the total surface area of the cuboid.
Python3
# Function to return the percentage increase# in the total surface area of the cuboid# Total surface area of a cuboid = 2(L * B) + (L * H) + (B * H)def increaseIntsa(L, B, H, l, b, h): oldsurfacearea = 2*((L * B) + (L * H) + (B * H)) newsurfacearea = 2*((L + (L * l * 0.01))*(B + (B * b*0.01)) + (L + (L * l * 0.01))*(H + (H * h*0.01)) + (B + (B * b * 0.01))*(H + (H * h*0.01))) increase = (newsurfacearea - oldsurfacearea) increasepercent = (increase / oldsurfacearea) * 100 return(increasepercent)# Cuboid dimensionsL = 20B = 30H = 50# percentage increasel = 10b = 12h = 15print(increaseIntsa(L, B, H, l, b, h), "%") |
Output :
26.974193548387092 %
