# Percentage increase in the volume of cuboid if length, breadth and height are increased by fixed percentages

Given a cuboid and three integers L, B and H. If the length of the cuboid is increased by L%, breadth is increased by B% percent and height is increased by H% percent. The task is to find the percentage increase in the volume of the cuboid.

Examples:

Input: L = 50, B = 20, H = 10
Output: 98%

Input: L = 10, B = 20, H = 30
Output: 71.6%

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach: Suppose the original length, breadth and height of the cuboid be l, b and h respectively. Now, the increased length will be (l + ((L * l) / 100)) i.e. increasedLength = l * (1 + (L / 100)). Similarly, increased breadth and height will be increasedBeadth = b * (1 + (B / 100)) and increasedHeight = h * (1 + (H / 100)).
Now, calculate originalVol = l * b * h and increasedVol = increasedLength * increasedBreadth * increasedHeight.
And, the percentage increase can be found as ((increasedVol – originalVol) / originalVol) * 100

(((l * (1 + (L / 100)) * b * (1 + (B / 100)) h * (1 + (H / 100))) – (l * b * h)) / (l * b * h)) * 100
((l * b * h * (((1 + (L / 100)) * (1 + (B / 100)) * (H / 100)) – 1)) / (l * b * h)) * 100
(((1 + (L / 100)) * (1 + (B / 100)) * (1 + (H / 100))) – 1) * 100

Below is the implementation of the above approach:

## C++

 // C++ implementation of the approach #include using namespace std;    // Function to return the percentage increase // in the volume of the cuboid double increaseInVol(double l, double b, double h) {     double percentInc = (1 + (l / 100))                         * (1 + (b / 100))                         * (1 + (h / 100));     percentInc -= 1;     percentInc *= 100;        return percentInc; }    // Driver code int main() {     double l = 50, b = 20, h = 10;     cout << increaseInVol(l, b, h) << "%";        return 0; }

## Java

 // Java implementation of the approach class GFG {        // Function to return the percentage increase // in the volume of the cuboid static double increaseInVol(double l,                                double b,                              double h) {     double percentInc = (1 + (l / 100)) *                          (1 + (b / 100)) *                          (1 + (h / 100));     percentInc -= 1;     percentInc *= 100;        return percentInc; }    // Driver code public static void main(String[] args) {     double l = 50, b = 20, h = 10;     System.out.println(increaseInVol(l, b, h) + "%"); } }    // This code is contributed by Code_Mech

## Python3

 # Python3 implementation of the approach    # Function to return the percentage increase # in the volume of the cuboid def increaseInVol(l, b, h):     percentInc = ((1 + (l / 100)) *                    (1 + (b / 100)) *                    (1 + (h / 100)))     percentInc -= 1     percentInc *= 100        return percentInc    # Driver code l = 50 b = 20 h = 10 print(increaseInVol(l, b, h), "%")    # This code is contributed by Mohit Kumar

## C#

 // C# implementation of the approach using System;    class GFG {        // Function to return the percentage increase // in the volume of the cuboid static double increaseInVol(double l,                              double b,                              double h) {     double percentInc = (1 + (l / 100)) *                          (1 + (b / 100)) *                          (1 + (h / 100));     percentInc -= 1;     percentInc *= 100;        return percentInc; }    // Driver code public static void Main() {     double l = 50, b = 20, h = 10;     Console.WriteLine(increaseInVol(l, b, h) + "%"); } }    // This code is contributed by Code_Mech

Output:

98%

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Improved By : mohit kumar 29, Code_Mech

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