Some of the classical problems in programming domain come from different categories and one among them is finding the max of subsets. This particular problem is also common when we need to compute the max and store consecutive group max value. Let’s try different approaches to this problem in python language.

**Method #1 : Using list comprehension + max()**

The list comprehension can be used to perform this particular task to filter out successive groups and max function can be used to get the max of the filtered solution.

`# Python3 code to demonstrate ` `# Maximum element in consecutive subsets ` `# using list comprehension + max() ` ` ` `# initializing list ` `test_list ` `=` `[` `4` `, ` `7` `, ` `8` `, ` `10` `, ` `12` `, ` `15` `, ` `13` `, ` `17` `, ` `14` `] ` ` ` `# printing original list ` `print` `(` `"The original list : "` `+` `str` `(test_list)) ` ` ` `# using list comprehension + max() ` `# Maximum element in consecutive subsets ` `res ` `=` `[ ` `max` `(test_list[x : x ` `+` `3` `]) ` ` ` `for` `x ` `in` `range` `(` `0` `, ` `len` `(test_list), ` `3` `)] ` ` ` `# printing result ` `print` `(` `"The grouped maximized list is : "` `+` `str` `(res)) ` |

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*filter_none*

**Output :**

The original list : [4, 7, 8, 10, 12, 15, 13, 17, 14] The grouped maximized list is : [8, 15, 17]

**Method #2 : Using max() + itertools.islice()**

The task of slicing the list into chunks is done by islice method here and the conventional task of getting the maximum is done by the max function as the above method.

`# Python3 code to demonstrate ` `# Maximum element in consecutive subsets ` `# using itertools.islice() + max() ` `import` `itertools ` ` ` `# initializing list ` `test_list ` `=` `[` `4` `, ` `7` `, ` `8` `, ` `10` `, ` `12` `, ` `15` `, ` `13` `, ` `17` `, ` `14` `] ` ` ` `# printing original list ` `print` `(` `"The original list : "` `+` `str` `(test_list)) ` ` ` `# using itertools.islice() + max() ` `# Maximum element in consecutive subsets ` `res ` `=` `[` `max` `(` `list` `(itertools.islice(test_list, i, i ` `+` `3` `))) ` ` ` `for` `i ` `in` `range` `(` `0` `, ` `len` `(test_list), ` `3` `)] ` ` ` `# printing result ` `print` `(` `"The grouped maximized list is : "` `+` `str` `(res)) ` |

*chevron_right*

*filter_none*

**Output :**

The original list : [4, 7, 8, 10, 12, 15, 13, 17, 14] The grouped maximized list is : [8, 15, 17]

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