We are given a binary string containing 1’s and 0’s. Find maximum length of consecutive 1’s in it.

**Examples:**

Input : str = '11000111101010111' Output : 4

We have existing solution for this problem please refer Maximum consecutive one’s (or zeros) in a binary array link. We can solve this problem within single line of code in Python. Approach is very simple,

- Separate all sub-strings of consecutive 1’s separated by zeros using split() method of string.
- Print maximum length of splited sub-strings of 1’s.

# Function to find Maximum legth of consecutive 1's in a binary string def maxConsecutive1(input): # input.split('0') --> splits all sub-strings of consecutive 1's # separated by 0's, output will be like ['11','1111','1','1','111'] # map(len,input.split('0')) --> map function maps len function on each # sub-string of consecutive 1's # max() returns maximum element from a list print max(map(len,input.split('0'))) # Driver program if __name__ == "__main__": input = '11000111101010111' maxConsecutive1(input)

Output:

4

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