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Python – List Words Frequency in String

  • Last Updated : 08 Jun, 2021

Given a List of Words, Map frequency of each to occurrence in String.

Input : test_str = ‘geeksforgeeks is best for geeks and best for CS’, count_list = [‘best’, ‘geeksforgeeks’, ‘computer’] 
Output : [2, 1, 0] 
Explanation : best has 2 occ., geeksforgeeks 1 and computer is not present in string.
Input : test_str = ‘geeksforgeeks is best for geeks and best for CS’, count_list = [‘better’, ‘gfg’, ‘computer’] 
Output : [0, 0, 0] 
Explanation : No word from list present in string. 
 

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Method #1 : Using defaultdict() + loop + list comprehension



In this, we compute words frequency using loop + defaultdict() and then use list comprehension to get all the counts corresponding to list of words.

Python3




# Python3 code to demonstrate working of
# Divide String into Equal K chunks
# Using list comprehension
from collections import defaultdict
 
# initializing strings
test_str = 'geeksforgeeks is best for geeks and best for CS'
 
# printing original string
print("The original string is : " + str(test_str))
 
# initializing count_list
count_list = ['best', 'geeksforgeeks', 'computer', 'better', 'for', 'and']
 
# computing frequency
res = defaultdict(int)
for sub in test_str.split():
    res[sub] += 1
     
# assigning to list words
res = [res[sub] for sub in count_list]
 
# printing result
print("The list words frequency : " + str(res))
Output
The original string is : geeksforgeeks is best for geeks and best for CS
The list words frequency : [2, 1, 0, 0, 2, 1]

Method #2 : Using Counter() + list comprehension

In this, Counter() is used to perform task of computing frequency, post that, list comprehension is used to assign frequency to list words.

Python3




# Python3 code to demonstrate working of
# Divide String into Equal K chunks
# Using list comprehension
from collections import Counter
 
# initializing strings
test_str = 'geeksforgeeks is best for geeks and best for CS'
 
# printing original string
print("The original string is : " + str(test_str))
 
# initializing count_list
count_list = ['best', 'geeksforgeeks', 'computer', 'better', 'for', 'and']
 
# computing frequency using Counter()
res = Counter(test_str.split())
     
# assigning to list words
res = [res[sub] for sub in count_list]
 
# printing result
print("The list words frequency : " + str(res))
Output
The original string is : geeksforgeeks is best for geeks and best for CS
The list words frequency : [2, 1, 0, 0, 2, 1]



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