# Python – Sort String list by K character frequency

• Last Updated : 25 Aug, 2021

Given String list, perform sort operation on basis of frequency of particular character.

Input : test_list = [“geekforgeekss”, “is”, “bessst”, “for”, “geeks”], K = ‘s’
Output : [‘bessst’, ‘geekforgeekss’, ‘geeks’, ‘is’, ‘for’]
Explanation : bessst has 3 occurrence, geeksforgeekss has 3, and so on.
Input : test_list = [“geekforgeekss”, “is”, “bessst”], K = ‘e’
Output : [“geekforgeekss”, “bessst”, “is”]
Explanation : Ordered decreasing order of ‘e’ count.

Method #1 : Using sorted() + count() + lambda

In this, sorted() is used to perform task of sort, count() is as function upon which sorting is to be performed. using additional key param, and function encapsulation used is lambda.

## Python3

 `# Python3 code to demonstrate working of``# Sort String list by K character frequency``# Using sorted() + count() + lambda` `# initializing list``test_list ``=` `[``"geekforgeeks"``, ``"is"``, ``"best"``, ``"for"``, ``"geeks"``]` `# printing original list``print``(``"The original list is : "` `+` `str``(test_list))` `# initializing K``K ``=` `'e'` `# "-" sign used to reverse sort``res ``=` `sorted``(test_list, key ``=` `lambda` `ele: ``-``ele.count(K))` `# printing results``print``(``"Sorted String : "` `+` `str``(res))`
Output
```The original list is : ['geekforgeeks', 'is', 'best', 'for', 'geeks']
Sorted String : ['geekforgeeks', 'geeks', 'best', 'is', 'for']```

Method #2 : Using sort() + count() + lambda

In this, we perform task of sort using sort(), this is similar to above, only difference being that sorting is done inplace.

## Python3

 `# Python3 code to demonstrate working of``# Sort String list by K character frequency``# Using sort() + count() + lambda` `# initializing list``test_list ``=` `[``"geekforgeeks"``, ``"is"``, ``"best"``, ``"for"``, ``"geeks"``]` `# printing original list``print``(``"The original list is : "` `+` `str``(test_list))` `# initializing K``K ``=` `'e'` `# "-" sign used to reverse sort``# inplace sort``test_list.sort(key ``=` `lambda` `ele: ``-``ele.count(K))` `# printing results``print``(``"Sorted String : "` `+` `str``(test_list))`
Output
```The original list is : ['geekforgeeks', 'is', 'best', 'for', 'geeks']
Sorted String : ['geekforgeeks', 'geeks', 'best', 'is', 'for']```

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