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Python | Handling no element found in index()
  • Last Updated : 27 Sep, 2019

Sometimes, while working with Python lists, we are confronted with a problem in which we need to check whether an element is present in a list and also where exactly, which index it occurs. The convenient solution of it is to use index(). But problem with this can come that sometimes, the desired element might not be present in the list. Let’s discuss a method in which this exception can be handled.

Method : Using ValueError + try + except

In this method, knowing that the value might not exists, we catch the error in try-except block. The ValueError is raised in the absence and can be used to catch this particular exception.





# Python3 code to demonstrate working of
# Handling no element found in index()
# Using try + except + ValueError
# initializing list
test_list = [6, 4, 8, 9, 10]
# printing list
print("The original list : " + str(test_list))
# Handling no element found in index()
# Using try + except + ValueError
try :
    res = "Element found"
except ValueError :
    res = "Element not in list !"
# Printing result
print("The value after catching error : " + str(res))


Output :

The original list : [6, 4, 8, 9, 10]
The value after catching error : Element not in list!

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