# Python – Flatten Nested Dictionary to Matrix

Sometimes, while working with data, we can have a problem in which we need to convert nested dictionary into Matrix, each nesting comprising of different row in matrix. This can have applicaition in many data domains. Lets discuss certain ways in which this task can be performed.

Method #1 : Using loop +` zip() + map()`
The combination of above functions can be used to perform this task. In this, we use brute force to flatten the dictionary keys and then use map() and zip() to align them as rows of matrix.

 `# Python3 code to demonstrate working of  ` `# Flatten Nested Dictionary to Matrix ` `# using zip() + loop + map() ` `   `  `# initializing dictionary  ` `test_dict ``=` `{``'Gfg1'` `: {``'CS'``:``1``, ``'GATE'` `: ``2``},  ` `             ``'Gfg2'` `: {``'CS'``:``2``, ``'GATE'` `: ``3``}, ` `             ``'Gfg3'` `: {``'CS'``:``4``, ``'GATE'` `: ``5``}}  ` `   `  `# printing original dictionary  ` `print``(``"The original dictionary is : "` `+` `str``(test_dict))  ` ` `  `# Flatten Nested Dictionary to Matrix ` `# using zip() + loop + map() ` `temp ``=` `list``(test_dict.values()) ` `sub ``=` `set``() ` `for` `ele ``in` `temp: ` `    ``for` `idx ``in` `ele: ` `        ``sub.add(idx)  ` `res ``=` `[] ` `res.append(sub) ` `for` `key, val ``in` `test_dict.items(): ` `    ``temp2 ``=` `[] ` `    ``for` `idx ``in` `sub: ` `        ``temp2.append(val.get(idx, ``0``)) ` `    ``res.append(temp2) ` ` `  `res ``=` `[[idx ``for` `idx, val ``in` `test_dict.items()]] ``+` `list``(``map``(``list``, ``zip``(``*``res))) ` `   `  `# printing result   ` `print``(``"The Grouped dictionary list is : "` `+` `str``(res))  `

Output :

The original dictionary is : {‘Gfg3’: {‘GATE’: 5, ‘CS’: 4}, ‘Gfg1’: {‘GATE’: 2, ‘CS’: 1}, ‘Gfg2’: {‘GATE’: 3, ‘CS’: 2}}
The Grouped dictionary list is : [[‘Gfg3’, ‘Gfg1’, ‘Gfg2’], [‘GATE’, 5, 2, 3], [‘CS’, 4, 1, 2]]

Method #2 : Using `union()` + list comprehension
The combination of above methods can be used to perform this task. In this, we compute the union using union() rather than the nested loops. The result is compiled using list comprehension.

 `# Python3 code to demonstrate working of  ` `# Flatten Nested Dictionary to Matrix ` `# using union() + list comprehension ` `   `  `# initializing dictionary  ` `test_dict ``=` `{``'Gfg1'` `: {``'CS'``:``1``, ``'GATE'` `: ``2``},  ` `             ``'Gfg2'` `: {``'CS'``:``2``, ``'GATE'` `: ``3``}, ` `             ``'Gfg3'` `: {``'CS'``:``4``, ``'GATE'` `: ``5``}}  ` `   `  `# printing original dictionary  ` `print``(``"The original dictionary is : "` `+` `str``(test_dict))  ` ` `  `# Flatten Nested Dictionary to Matrix ` `# using union() + list comprehension ` `temp ``=` `set``().union(``*``test_dict.values()) ` `res ``=` `[``list``(test_dict.keys())] ` `res ``+``=` `[[key] ``+` `[sub.get(key, ``0``) ``for` `sub ``in` `test_dict.values()] ``for` `key ``in` `temp] ` `   `  `# printing result   ` `print``(``"The Grouped dictionary list is : "` `+` `str``(res))  `

Output :

The original dictionary is : {‘Gfg3’: {‘GATE’: 5, ‘CS’: 4}, ‘Gfg1’: {‘GATE’: 2, ‘CS’: 1}, ‘Gfg2’: {‘GATE’: 3, ‘CS’: 2}}
The Grouped dictionary list is : [[‘Gfg3’, ‘Gfg1’, ‘Gfg2’], [‘GATE’, 5, 2, 3], [‘CS’, 4, 1, 2]]

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